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3 years ago

The problem has been started for you 780 divided by 9 What is the quotient

Mathematics

1 answer:

postnew [5]3 years ago

3 0

86.6 would be the correct answer to your question 780/9=86.6....

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3(r-6)+2=4(r+2)-21 . Find the value for r?

galben [10]

3(r-6)+2=4(r+2)-21
3r-18+2=4r+8-21
3r-16=4r-13
-3=r

r=-3

8 0

3 years ago

Evaluate the function f(-2) - h(4) given the following functions: f(x) = 4x 2+ 9 h(x) = 3x - 14

Goryan [66]

Answer:

-86

Step-by-step explanation:

simplify each equation as much as possible

f(x)= 4x(2+9) add

4x(11) multiply

f(x)=44x

substitute given numbers into each equation

44(-2)=-88 3(4)-14= 12-14=-2

combine equations

-88-(-2)= -86 add since you are subtracting a negative number

4 0

2 years ago

How much warmer is 12°C than -20°C?

zvonat [6]

To put it simply, 12 degrees C is 12 away from 0 and -20 degrees C is 20 away from 0. Taking these two inputs and adding them together should give you 32. So 12 degrees C is 32 degrees warmer than -20 degrees C

8 0

2 years ago

Read 2 more answers

Perform the indicated operation. Be sure the answer is reduced.

avanturin [10]

<h3>Given Equation:-</h3>

$\boxed{ \rm \frac{4x^{2}y^{3}z}{9} \times \frac{45y}{8 {x}^{5} {z}^{5} }}$

<h3>Step by step expansion:</h3>

$\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times \dfrac{45y}{8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times \dfrac{45y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z}{1} \times \dfrac{5y}{2{x}^{3} {z}^{3} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }$

$\\ \\$

$\dashrightarrow \sf\dfrac{y^{3}}{1} \times \dfrac{5y}{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y \times {y}^{3} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5y {}^{0} \times {y}^{3 + 1} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \sf \dfrac{5 \times {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\dashrightarrow \bf \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }$

$\\ \\$

$\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}$

8 0

1 year ago

On the coordinate plane, the four corners of Alejandro's garden are located at (0,2), (4,6), (8,2), and (4,-2). Which shape most

ohaa [14]

It is the shape of a rectangle

6 0

3 years ago

Read 2 more answers