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alukav5142 [94]
3 years ago
13

Find the ratio, pls answer quick​

Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0

Answer:

1) 1:10

2) 150:2

3) 1:3

4) 20hrs : 1hrs

Step-by-step explanation:

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Yea so like anyone know this​
lianna [129]

Answer:

=13p+7

Step-by-step explanation:

Let's simplify step-by-step.

5p+11+8p−4

=5p+11+8p+−4

Combine Like Terms:

=5p+11+8p+−4

=(5p+8p)+(11+−4)

=13p+7

4 0
3 years ago
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If you have a balance of $270 in your bank account each month you deposit $45 let January=1 February=2 and so on. Write any equa
marissa [1.9K]

Answer:

$540

Step-by-step explanation:

We are given that the initial balance in the bank account is $270.

We are then told that every month $45 is added to the account.

To find the equation that tells us the balance at any point in time assuming no interest is added or money is taken out, we can first understand the constant, y=270.

This gives us the initial value of the balance and any changes to the balance will start from this point.

Let x be the time in months.

if we let y=270 + 45x, we find the value of the function accounting for the addition of money every month.

Assuming money is put in during January; substituting the number of months as x=6 (since it is June), we can find the balance in June.

y=270 +45(6)=540

Hence, the balance in June is $540

8 0
3 years ago
Is 0.83 equal to 83/100
ipn [44]

Answer:

Yes.

Step-by-step explanation:

83/100=0.83 : )

4 0
3 years ago
Read 2 more answers
ANSWER PLEASE LORD ANSWER
sesenic [268]

Answer:

< 2.11, 4.53 >, < -3.03, -1.75 >, <2.93 cos 108.26, 2.93 sin 108.26 >

Step-by-step explanation:

First, let's decompose Bruce's velocity along the x- and y- direction. Bruce is moving 5 m/s at 25 degrees east of north, so its angle with respect to the positive x-direction is actually 90 - 25 = 65 degrees. So its components are

b_x = (5 m/s) cos 65^{\circ} =2.11 m/s\\b_y = (5 m/s) sin 65^{\circ} =4.53 m/s

So, Bruce's vector is

< 2.11, 4.53 >

The current is moving 3.5 m/s at an angle 60 degrees west of south, which means an overall angle of 210 degrees, measured counterclockwise from the positive x-axis. So, the components of the current's velocity are

c_x = (3.5 m/s) cos 210^{\circ}=-3.03 m/s\\c_y = (3.5 m/s) sin 210^{\circ}=-1.75 m/s

So, the current's vector is

< -3.03, -1.75 >

Finally, we can add the components of the two vectors to find Bruce's actual velocity:

v_x = b_x + c_x = 2.11 + (-3.03)=-0.92 m/s\\v_y = b_y + c_y = 4.53+(-1.75)=2.78 m/s

So, Bruce's actual velocity is

< -0.92, 2.78 >

The magnitude is

v=\sqrt{(-0.92)^2+(2.78)^2}=2.93 m/s

And the direction is

\theta=180^{\circ} - tan^{-1} (\frac{v_y}{v_x})=180^{\circ} - tan^{-1}(\frac{2.78}{-0.92})=180^{\circ}-71.7^{\circ}=108.3^{\circ}

5 0
3 years ago
Read 2 more answers
What is 41% of 53????
Law Incorporation [45]

Answer:

21.73

Step-by-step explanation:

calculator

8 0
3 years ago
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