If two line are perpendicular. The multiply of their slopes are equal to -1.
First line's slope is: -1/2x because if the line equation is form of y=ax+b a is slope.
Let say second line's slope is m
m.-1/2=-1 so m=2
y=ax+b is general form of linear function/equation. (a=slope)
y=2x+b
If this line passes through the point (2,-2),if we write -2 to y and 2 to x, the equation becomes true.
-2=4+b
b=-6
Thus,
y=2x-6 is true answer.
(xy)' + (2x)' + (3x^2)' = (4)'
y + xy' + 2 + 6x = 0
xy' = -y -2 -6x
y' = [-y -2 -6x] / x
Now solve y from the original equation and substitue
xy + 2x + 3x^2 = 4 => y = [-2x - 3x^2 + 4] / x
y' = [(-2x - 3x^2 +4) / x - 2 - 6x ] / x
y' = [-2x - 3x^2 + 4 -2x -6x^2 ] x^2 = [ -4x - 9x^2 + 4] / x^2 =
= [-9x^2 - 4x + 4] / x^2
Answer:
f = - 1
Step-by-step explanation:
f - 6 = f + 8
f - 6 = - (f + 8)
f ∈ ∅
f - 6 = - (f + 8)
Answer:
-79.8
Step-by-step explanation:
plug into a calculator, making sure to keep perenthesis in the correct places
Arrange the data set in ascending order:
State A: 4, 5, 6, 6, 7, 8, 9, 21, 25
State B: 10, 11, 12, 13, 14, 14, 15, 15, 16
5 number summary:
State A State B
minimum 4 10
Q1 5.5 11.5
median 7 14
Q3 15 15
maximum 25 16
IQR 9.5 3.5
The box plot are not symmetric. The distance of the median from each Q1 and Q3 should be equal for the box plot to be symmetric.
