After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
Step-by-step explanation:
You can find the amount of students each vehicle can carry by representing the two scenarios in equations.
You are trying to find how many students will fit in each bus or van, so the two variables used will be "b" to represent how many students can fit in a bus and "v" to represent how many students can fit in a van.
High school A used 1 van and 6 buses, so there will be 1"v" and 6"b" for 372 students.
High school B used 4 vans and 12 buses, so there will be 4"v" and 12"b" for 780 students.
Now, represent these in equations:

We can use substitution to solve this system:
can be rewritten as
after subtracting 6b from both sides. You can then substitute this new value of "v" into the other equation to solve for "b":

After solving for b, you can then substitute the new value of b into the other equation to find the value of v:

After solving for both variables, you find that each bus can hold 59 students and each van can hold 18 students.
Answer:
D
Step-by-step explanation:
The unmarked angle of the triangle is also 40o. The triangle is marked with two equal sides (isosceles).
<2 + 40 + 40 = 180 Combine the left
<2 + 80 = 180 Subtract 80 from both sides
<2 = 180 - 80
<2 = 100 degrees.
That's not the answer. We have to solve for x
<2 = x + 106
100 = x + 106 Subtract 106 from both sides
100 - 106 = x
x = - 6
The gradient formula is (y2-y1)/(x2-x1) aka rise/run, where by (x1,y1) and (x2,y2) are two points on the line.
In this case, the gradient
= -5-(-2))/(2-(-2))
= -3/4
- linear pairs are supplementary, meaning they add up to 180°
5x + 9 + 3x + 11 = 180
8x + 20 = 180
8x = 160
x = 20
- now plug in.
angle 1: 5(20) + 9 = 100 + 9 = 109°
angle 2: 3(20) + 11 = 60 + 11 = 71°