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ipn [44]
3 years ago
15

Calculate the value of x to one decimal place. a0inches

Mathematics
1 answer:
gtnhenbr [62]3 years ago
7 0

Answer:

Step-by-step eNow examine the right triangle on the left in the figure.

x%2F10=sin%2850%29, in reference to the 50 degree angle, hypotenuse is that slanted segment of 10 units, and "x" is the opposite side from the 50 degree angle.

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How many 3/4s are in 1​
kirza4 [7]

Answer and Step-by-step explanation:

There is 1\frac{1}{3} \frac{3}{4} in the number 1.

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

5 0
3 years ago
Zu questions
frutty [35]

Answer:

esfgkjfvgghhhhhhjjhhhhhgfffghjjkkokkkjrdgsgegfggy

7 0
3 years ago
I need help asap , im doing this thing and I cant do it im confused
aksik [14]

Answer:

they will be the same at 11 months

Step-by-step explanation:

the equations for this are

y = 40+55x

and

y = 165+30x

where x is the number of months

if you plug this into your graphic calc you see they are equal at 11 therefore, 11 months

6 0
3 years ago
Question 14. A carousel makes one complete revolution every 75 seconds. Levi sits on the carousel 4 feet from its center. If the
garik1379 [7]

Answer:

The correct option is;

H. 32·π

Step-by-step explanation:

The given information are;

The time duration for one complete revolution = 75 seconds

The distance from the center of the carousel where Levi sits = 4 feet

The time length of a carousel ride = 5 minutes

Therefore, the number of complete revolutions, n, in a carousel ride of 5 minutes is given by n = (The time length of a carousel ride)/(The time duration for one complete revolution)

n = (5 minutes)/(75 seconds) = (5×60 seconds/minute)/(75 seconds)

n = (300 s)/(75 s) = 4  

The number of complete revolutions - 4

The distance of 4 complete turns from where Levi seats = 4 ×circumference of circle of Levi's motion

∴ The distance of 4 complete turns from where Levi seats = 4 × 2 × π × 4 = 32·π.

3 0
3 years ago
I need step by step please 3(x-2)^2+1=13
Romashka-Z-Leto [24]

Answer:

x_{1} = 0. \:  \:  \:  x_{2} = 4

Step-by-step explanation:

3(x - 2)^{2}  + 1 = 3

3( {x}^{2}  - 4x + 4) + 1 = 13

{3x}^{2}  - 12x + 12 + 1 = 13

{3x}^{2}  - 12x + 13 = 13

{3x}^{2}  - 12x = 0

x \times (x - 4) = 0

x = 0

x - 4 = 0

\boxed{\green{x_{1} = 0. \:  \:  \:  x_{2} = 4}}

7 0
2 years ago
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