Answer with explanation:
→→→Function 1
f(x)= - x²+ 8 x -15
Differentiating once , to obtain Maximum or minimum of the function
f'(x)= - 2 x + 8
Put,f'(x)=0
-2 x+ 8=0
2 x=8
Dividing both sides by , 2, we get
x=4
Double differentiating the function
f"(x)= -2, which is negative.
Showing that function attains maximum at ,x=4.
Now,f(4)=-4²+ 8× 4-15
= -16 +32 -15
= -31 +32
=1
→→→Function 2:
f(x) = −x² + 2 x − 3
Differentiating once , to obtain Maximum or minimum of the function
f'(x)= -2 x +2
Put,f'(x)=0
-2 x +2=0
2 x=2
Dividing both sides by , 2, we get
x=1
Double differentiating the function,gives
f"(x)= -2 ,which is negative.
Showing that function attains maximum at ,x=1.
f(1)= -1²+2 ×1 -3
= -1 +2 -3
= -4 +2
= -2
⇒⇒⇒Function 1 has the larger maximum.
First, multiply the radius by itself. 5x5=25. Then multiply by pi, or 3.14. 25x3.14=78.5. The area of the circle is 78.5units^2. Hope this helps! ;)
Answer:
1
2
+
4
2
+
7
2
−
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.
−
(
3
−
2
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2
=
(
6
2
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3
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1
)
/
2
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
P = 2(L + W)
L = 4/3W
P = 2(4/3W + W) <=== part 1 is D
when P = 28
28 = 2(4/3W + W)
28/2 = 4/3W + 3/3W
14 = 7/3W
14 / (7/3) = W
14 * 3/7 = W
42/7 = W
6 = W....width is 6 inches
L = 4/3W
L = 4/3(6)
L = 24/3
L = 8....length is 8 inches
A = L * W
A = 8 * 6
A = 48 in^2 <==== part 2
