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2 years ago

Help me please I have no idea what the answer is

Mathematics

1 answer:

joja [24]2 years ago

4 0

Answer:

-21/10

Step-by-step explanation:

-2/5 - 4/5 = -6/5 <--

a common denominator

Then...

-6/5 -9/10 = -21/10

There is not a common denominator so you have to multiply 2 to the -6/5 to make it -12/10

The answer can be left as an improper fraction which is -21/10

or a mixed number -2 1/10 th

You might be interested in

Graph the system by using technology. What is the y-coordinate of the solution?

son4ous [18]

Take second equation here,
2x + 9 = -12
2x = -12 - 9
2x = -21
Multiply by 2,
4x = -42

Now, substitute the vaue of 4x in 1st equation,
-42 - y = 2
-y = 2 + 42
y = -44

In short, Your Answer would be -44

Hope this helps!

3 0

3 years ago

I don't need you to work it out, just theorem(s) i need to reach the answer :)

VikaD [51]

Not sure why such an old question is showing up on my feed...

Anyway, let $x=\tan^{-1}\dfrac43$ and $y=\sin^{-1}\dfrac35$ . Then we want to find the exact value of $\cos(x-y)$ .

Use the angle difference identity:

$\cos(x-y)=\cos x\cos y+\sin x\sin y$

and right away we find $\sin y=\dfrac35$ . By the Pythagorean theorem, we also find $\cos y=\dfrac45$ . (Actually, this could potentially be negative, but let's assume all angles are in the first quadrant for convenience.)

Meanwhile, if $\tan x=\dfrac43$ , then (by Pythagorean theorem) $\sec x=\dfrac53$ , so $\cos x=\dfrac35$ . And from this, $\sin x=\dfrac45$ .

So,

$\cos\left(\tan^{-1}\dfrac43-\sin^{-1}\dfrac35\right)=\dfrac35\cdot\dfrac45+\dfrac45\cdot\dfrac35=\dfrac{24}{25}$

7 0

3 years ago

!!!! PLEASE HELP !!!!!!

Keith_Richards [23]

Answer:

i got -8 but the closest is -7 so u can tried that

Step-by-step explanation:

5 0

3 years ago

consider the function f(x) = x2 2x – 15. what are the x-intercepts of the function? left-most x-intercept: ( , 0) right-most x-i

eimsori [14]

we have

$f(x)=x^{2} +2x-15$

we know that

The x-intercept is the value of x when the value of the function is equal to zero

in this problem

Find the roots of the function

equate the function to zero

$x^{2} +2x-15=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$x^{2} +2x=15$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2} +2x+1=15+1$

$x^{2} +2x+1=16$

Rewrite as perfect squares

$(x+1)^{2}=16$

Square root both sides

$(x+1)=(+/-)\sqrt{16}$

$(x+1)=(+/-)4$

$x=-1(+/-)4$

$x1=-1+4=3$

$x2=-1-4=-5$

$x^{2} +2x-15=(x-3)(x+5)$

therefore

<u>the answer is</u>

the x-intercepts are the points $(3,0)$ and $(-5,0)$

3 0

2 years ago

Read 2 more answers

6 (3x-1)-10x. with work please :)

STatiana [176]

Hey there!
Let's break this expression into two parts:
6(3x-1) and -10x

To solve the first part, we need to use the distributive property which states:
a(b+c) = ab+ac

Applying that to this problem, we have:
6(3x) + 6(-1) =
18x - 6

Now, we can take that -10x and put it right back in:

18x - 6 - 10x

Combine like terms and subtract the 10x from the 18x to get:
8x - 6

Hope this helps!

4 0

3 years ago

Help me please I have no idea what the answer is​

Help me please I have no idea what the answer is