When the diagonals of a quadrilateral are perpendicular, the area of that quadrilateral is half the product of their lengths.
.. A = (1/2)*d₁*d₂
Substituting the given information, this becomes
.. 58 in² = (1/2)*(14.5 in)*d₂
.. 2*58/14.5 in = d₂ = 8 in
The length of diagonal BD is 8 in.
Answer:
80 tickets
Step-by-step explanation:
Given the profit, y, modeled by the equation, y = x^2 – 40x – 3,200, where x is the number of tickets sold, we are to find the total number of tickets, x, that need to be sold for the drama club to break even. To do that we will simply substitute y = 0 into the given the equation and calculate the value of x;
y = x^2 – 40x – 3,200,
0 = x^2 – 40x – 3,200,
x^2 – 40x – 3,200 = 0
x^2 – 80x + 40x – 3,200 = 0
x(x-80)+40(x-80) = 0
(x+40)(x-80) = 0
x = -40 and x = 80
x cannot be negative
Hence the total number of tickets, x, that need to be sold for the drama club to break even is 80 tickets
Answer:
Angle ABD is 16 degrees and Angle DBC is 74 degrees
Step-by-step explanation:
Question 6. x+9+11x-3=90. 12x+6=90 -6 on both sides and 12x=84 divide each side by 12 and x= 7 angle ABD is x+9 so 7 +9= 16. Angle measure of ABD is 16 degrees. Measure of angle DBC is 11x -3 so 11 times 7=77. 77-3= 74. So the measure of angle DBC is 74 degrees and this answer is right because they both add up to be 90 degrees. Hope this helped! :)
Ummmmmmmmmmmm theeeee answerrrrrr isssssss 11,13
Answer:
a) 
b) 
And replacing we got:
![P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.2%2B0.3%2B0.1%5D%3D%200.4)
c) 
d) 
e) 
f) 
And replacing we got:

And the variance would be:
![Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4](https://tex.z-dn.net/?f=%20Var%28X0%20%3DE%28X%5E2%29-%20%5BE%28X%29%5D%5E2%20%3D%206.4%20-%282%5E2%29%3D%202.4)
And the deviation:

Step-by-step explanation:
We have the following distribution
x 0 1 2 3 4
P(x) 0.2 0.3 0.1 0.1 0.3
Part a
For this case:

Part b
We want this probability:

And replacing we got:
![P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4](https://tex.z-dn.net/?f=%20P%28X%20%5Cgeq%203%29%20%3D%201-%20%5B0.2%2B0.3%2B0.1%5D%3D%200.4)
Part c
For this case we want this probability:

Part d

Part e
We can find the mean with this formula:

And replacing we got:

Part f
We can find the second moment with this formula

And replacing we got:

And the variance would be:
![Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4](https://tex.z-dn.net/?f=%20Var%28X0%20%3DE%28X%5E2%29-%20%5BE%28X%29%5D%5E2%20%3D%206.4%20-%282%5E2%29%3D%202.4)
And the deviation:
