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Bess [88]
3 years ago
11

26 divided by 3 I’m horrible at matj

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
5 0
8.66666667 that’s your answer
Firlakuza [10]3 years ago
3 0
8.666666666666667, but to simply it i believe it would just be 8.6
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I need help on this question can some help
guapka [62]

Answer:There’s a that you can download with a ton of edginuity answers if you type down edginuity answers and hit the pdf by reservamesa and you can find some.

Step-by-step explanation:

5 0
3 years ago
Yall just use me 4 points }:
Klio2033 [76]

Answer:

thx.

Step-by-step explanation:

3 0
3 years ago
Test the set of polynomials for linear independence. If it is linearly dependent, express one of the polynomials as a linear com
aliina [53]

Answer:

The set of polynomial  is Linearly Independent.

Step-by-step explanation:

Given - {f(x) =7 + x, g(x) = 7 +x^2, h(x)=7 - x + x^2} in P^2

To find - Test the set of polynomials for linear independence.

Definition used -

A set of n vectors of length n is linearly independent if the matrix with these vectors as columns has a non-zero determinant.

The set is dependent if the determinant is zero.

Solution -

Given that,

f(x) =7 + x,

g(x) = 7 +x^2,

h(x)=7 - x + x^2

Now,

We can also write them as

f(x) = 7 + 1.x + 0.x²

g(x) = 7 + 0.x + 1.x²

h(x) = 7 - 1.x + 1.x²

Now,

The coefficient matrix becomes

A = \left[\begin{array}{ccc}7&1&0\\7&0&1\\7&-1&1\end{array}\right]

Now,

Det(A) = 7(0 + 1) - 1(7 - 7) + 0

           = 7(1) - 1(0)

           = 7 - 0 = 7

⇒Det(A) = 7 ≠ 0

As the determinant is non- zero ,

So, The set of polynomial  is Linearly Independent.

5 0
3 years ago
Which of the following relations is a function?
Anon25 [30]

Answer:

D.(5,1),(-5,4),(2,1),(5,2)

6 0
3 years ago
Read 2 more answers
Need help now!!!!! :)
brilliants [131]
The 5 is the coefficient...

6 0
3 years ago
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