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3 years ago

What is the slope of the line

Mathematics

2 answers:

bulgar [2K]3 years ago

8 0

The slope is is 2

Rise over run
Rise 2
Run 1

Kisachek [45]3 years ago

5 0

Answer:

Step-by-step explanation:

We can use the points (-3, 0) and (1, 4) to solve.

The slope formula is [ y2-y1/x2-x1 ]

4-0/1-(-3)

4/4

Best of Luck!

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Stolb23 [73]

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Select the correct answer. Which expression is equivalent to x + y + x + y + 3(y + 5)? A. 2x + 5y + 5 B. 2x + y + 30 C. 2x + 5y

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Answer:

Step-by-step explanation:

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Types of bonds are divided into three categories: good risk, medium risk, and poor risk. Assume that of a total of 11, 332 bonds

Alekssandra [29.7K]

Answer:

Probabilty of not poor= 0.75

Step-by-step explanation:

total of 11332 bonds.

7311 are good risk.

1182 are medium risk.

Poor risk

= total risk-(good risk+ medium risk)

= 11332-(7311+1182)

= 11332-8493

= 2839.

Poor risk = 2839

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= 0.7495

To two decimal place= 0.75

3 0

3 years ago

Find the value of x.

Mandarinka [93]

Answer:

⏩12°

Step-by-step explanation:

4x + 7° + 35° = 90° {being complementary angles }

4x + 42° = 90°

4x = 90° - 42°

4x = 48°

x = 48° / 4

x = 12°

Hope it will help :)❤

6 0

3 years ago

Read 2 more answers

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 
$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

use $x^3 - y^3 = (x-y)(x^2 + xy + y^2)$ and $x^3 + y^3 = x^2 - xy + y^2$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)$

so $\sin^2 A + \cos^2 A = 1$

$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side$

4 0

3 years ago

What is the slope of the line​

What is the slope of the line