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EastWind [94]
3 years ago
6

heights of statistics students were obtained by a teacher as part of an experiment conducted for the class. The last digit of th

ose heights are listed below. Construct a frequency distribution with 10 classes. Based on the​ distribution, do the heights appear to be reported or actually​ measured? What can be said about the accuracy of the​ results? 0 0 0 0 0 0 0 0 0 1 2
Mathematics
1 answer:
hammer [34]3 years ago
7 0

Answer:

1) B. The height appear to be reported because there are disproportionately more 0s and 5s.

2) A. They are likely not very accurate because they appear to be reported.

Step-by-step explanation:

The distribution table is shown below:

Last Digit           Frequency

     0                          9

     1                           1

     2                          1

     3                          3

     4                          1

     5                         11

     6                          1

     7                          0

     8                          3

     9                          1

1. Based on the distribution table, we see a very disproportionate distribution. There is a high frequency of 0's and 5's. This lays credence to the heights being reported rather than measured. As such, option B is the correct answer

<u>B. The height appear to be reported because there are disproportionately more 0s and 5s</u>.

2. Since the heights were reported and not measured, they are most certainly not accurate. The conclusion is that the result is not accurate. As such, option A is the correct answer

<u>A. They are likely not very accurate because they appear to be reported</u>.

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Notice that the line with negative slope has a y-intercept of 5 and the line with positive slope has a y-intercept of 2.

On the other hand, the slope of the line with negative slope is -2, while the slope of the line with positive slope is 3 (This can be identified since in one case, the value of y decreases by 2 for each increase of 1 unit in x, and in the other, the value of y increases by 3 for each increase of 1 unit in x).

Using the y-intercept form to represent each line, the system of equations represented by the graph must be equivalent to:

\begin{gathered} y=-2x+5 \\ y=3x+2 \end{gathered}

From the given options, the one that displays the correct system of equations is option A.

Therefore, the answer is:

\begin{gathered} A) \\ y=3x+2 \\ y=-2x+5 \end{gathered}

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1 year ago
What is the volume of the composite figure shown? (Use 3.14 for π.)
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4 years ago
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the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\ 2x+8y=12 \ \ |-2x \\ \\8y=-2x+12\ \ /:8\\ \\y=-\frac{2}{8}x+\frac{12}{8}

y=-\frac{1}{4}x+\frac{3}{4}\\ \\ m=-\frac{1}{4}



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3 years ago
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Answer:

What about

Step-by-step explanation:

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lesantik [10]
Answers:
The formula is [f(-1)-f(-4)]/[3]
The value of f(-1) is 3
The value of f(-4) is -3
The average rate of change is 2

==============================================

Explanation:

For the first blank, we use the formula
[ f(b) - f(a) ]/[ b - a ]
where 'a' and 'b' are the endpoints for the x interval

In this case, a = -4 and b = -1. When you plug those values into the formula above, you get...
[ f(b) - f(a) ]/[ b - a]
[ f(-1) - f(-4)]/[ -1 - (-4) ] 
[ f(-1) - f(-4)]/[ -1+4 ]
[ f(-1) - f(-4)]/[ 3 ]
which is why the answer is choice C for the first blank

-------------------------------------------

To compute the value of f(-1), we draw a vertical line through -1 on the x axis. This vertical line crosses the diagonal function graph at the point (-1,3). The y value of this point is what we want. Plugging in x = -1 leads to y = 3. This is why f(-1) = 3
If you want, you can draw a horizontal line through (-1,3) and you'll see it touching 3 on the y axis.

-------------------------------------------

Follow similar steps as above to compute f(-4). Draw a vertical line through x = -4 on the x axis. Mark the point where the vertical line crosses the diagonal line. This point is (-4,-3). Optionally draw a horizontal line over til you hit the y axis and you'll find that y = -3 corresponds to x = -4

This is why f(-4) = -3

-------------------------------------------

We'll use the last three sections to compute the average rate of change. Everything combines together building up to this moment.

From the first part, we had the formula
[ f(b) - f(a) ]/[ b - a ]
[ f(-1) - f(-4)]/[ 3 ]

We can replace the "f(-1)" with 3 since we found that f(-1) = 3
Similarly, f(-4) = -3 so we can replace the "f(-4)" with -3

Doing those replacements and simplifying leads to...

[ f(-1) - f(-4)]/[ 3 ]
[ 3 - (-3)]/[ 3 ]
[ 3 + 3]/[ 3 ]
6/3
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So the average rate of change is 2

Note: because the entire graph is a straight line, the average rate of change for any interval a < x < b is going to be equal to the slope m. In this case, the slope of the line is m = 2/1 = 2. We move up 2 units each time we move to the right 1 unit along the diagonal line.

6 0
3 years ago
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