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3 years ago

A dilation is a transformation whose preimage and image are

Mathematics

1 answer:

Sergeeva-Olga [200]3 years ago

3 0

A different size but not does not change shape.

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Someone please help with this middle school math lol

vlabodo [156]

#1 is 65 by 75, next is 3 by 9, and the last is 75 by 25

4 0

3 years ago

1. When you multiply an equation by a value, are you changing the solutions of that equation? Explain. 44 POINTS!!

jolli1 [7]

Answer: Yes. When you solve your equations, you're solutions will change a little bit. It's good because it'll give you the right answer.

I hope this helps you and I hope it's right. ☺

3 0

3 years ago

PLEASEE HELP WILL GIVE BRAINLEST 20 POINTS

Ket [755]

<h3>Answer:</h3>

For each birdhouse built, the total cost increases by $3.50.

<h3>Step-by-step explanation:</h3>

Let's try some of the answers and see if they work.

The "initial cost" will be the cost when 0 birdhouses are built.

... f(0) = 3.5·0 +24 = 24 . . . . . clearly, not $3.50

Then increasing the number of birdhouses by 1, the cost is ...

... f(1) = 3.5·1 +24 = 27.5 . . . . . the cost has gone up (not down) by $3.50

Clearly the total cost to build 1 birdhouse is not $3.50. (It is $27.50.)

___

Our exploration of the formula leads us to conclude ...

... For each birdhouse built, the total cost increases by $3.50.

5 0

3 years ago

W/2 - 6= -10 Solve for W<br><br> Please and thank you because I’m stupid

Whitepunk [10]

Answer:

w=-8

Step-by-step explanation:

1. add 6 to -10 (-4)

2. multilpy by 2 (-8)

3 0

3 years ago

It has a time to failure distribution which is normal with a mean of 35,000 vehicle miles and a standard deviation of 7,000 vehi

Triss [41]

Answer:

The designed life should be of 21,840 vehicle miles.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 35,000 vehicle miles and a standard deviation of 7,000 vehicle miles.

This means that $\mu = 35000, \sigma = 7000$

Find its designed life if a .97 reliability is desired.

The designed life should be the 100 - 97 = 3rd percentile(we want only 3% of the vehicles to fail within this time), which is X when Z has a p-value of 0.03, so X when Z = -1.88.

$Z = \frac{X - \mu}{\sigma}$

$-1.88 = \frac{X - 35000}{7000}$

$X - 35000 = -1.88*7000$

$X = 21840$

The designed life should be of 21,840 vehicle miles.

3 0

2 years ago