Answer: 1/70
Step-by-step explanation:
This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.
Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,
then the probability of figure "8" starting phone number = 1/7
Since all 10 numbers can possibly end a phone number,
then the probability of having figure "8" as the last digit of a phone number = 1/10
Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.
The diameter can be obtained by the formula A = pi*r^2
First, multiply 0.50 * 100 to obtain the area of the ball, then simplify and solve for the radius. Doubling the radius would yield the diameter. This is shown below:
Area of the ball = 0.50 * 100 = 50 in^2
<span>A = pi*r^2
</span>50 = (3.14)*r^2
r = 3.99 = approx. 4
diameter = 2r
Diameter = 8 inches.
Among the choices, the correct answer is C. 8.0 in.
Answer:
not
Step-by-step explanation:
![\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] *\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]=](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%2A%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%3D)
First is A and Second is B
Let's find A*B
![\left[\begin{array}{ccc}-2(-2)+4*3&-2*1+4*7\\1(-2)+3*3&1*1+3*7\end{array}\right] =\left[\begin{array}{ccc}16&26\\7&22\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%28-2%29%2B4%2A3%26-2%2A1%2B4%2A7%5C%5C1%28-2%29%2B3%2A3%261%2A1%2B3%2A7%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D16%2626%5C%5C7%2622%5Cend%7Barray%7D%5Cright%5D)
b)
![\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right] \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%261%5C%5C3%267%5Cend%7Barray%7D%5Cright%5D%20%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%264%5C%5C1%263%5Cend%7Barray%7D%5Cright%5D%20%3D)
Now let's find B*A
![\left[\begin{array}{ccc}-2(-2)+1*1&-2*4+1*3\\3(-2)+7*1&3*4+7*3\end{array}\right] =\left[\begin{array}{ccc}5&-5\\1&23\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%28-2%29%2B1%2A1%26-2%2A4%2B1%2A3%5C%5C3%28-2%29%2B7%2A1%263%2A4%2B7%2A3%5Cend%7Barray%7D%5Cright%5D%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-5%5C%5C1%2623%5Cend%7Barray%7D%5Cright%5D)
c) They are not
The answer to the problem is 220
Answer:
eegstecation
Yea YEA
Step-by-step explanation: