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saw5 [17]
3 years ago
13

How do you solve 2(3k+4)=10

Mathematics
2 answers:
bezimeni [28]3 years ago
6 0

The answer would be: k= 1/3

Here’s how you solve it!

First you want to divide both sides by 2

Now you are left with this:

3k+4=5

Now you want to move 4 to the other side causing it to change into a negative.

3k=5-4

Now subtract 5-4 to get 1

3k= 1

Now divide both sides by 3

K= 1/3

Now you are left with your answer: K= \frac{1}{3}

Hope this helps! :3

Alexeev081 [22]3 years ago
3 0
3k+4=10/2
3k+4=5
3k=5-4
3k=1
K=1/3
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Assume every 10-digit natural number is a possible telephone number except those that begin with 0, 1 or 2. What fraction of tel
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Answer: 1/70

Step-by-step explanation:

This is a question that can also be interpreted as what is the probability of having the first number of a phone number to be 8 and the last number of the phone number to also be 8. This answer gives the fraction of the phone numbers that starts with 8 and end with 8.

Since three numbers (0,1,2) cannot start a phone number and we are left to pick from 7 numbers,

then the probability of figure "8" starting phone number = 1/7

Since all 10 numbers can possibly end a phone number,

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Hence probability of having "8" as the first and last digit of a phone number = fraction of total telephone numbers that begin with digit 8 and end with digit 8 = 1/7 × 1/10 = 1/70.

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3 years ago
Ruby red paint costs $0.50 per square inch. A ball is painted ruby red and costs $100.00 to paint. What is the diameter of the b
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The diameter can be obtained by the formula A = pi*r^2

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not

Step-by-step explanation:

\left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] *\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]=

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b)

\left[\begin{array}{ccc}-2&1\\3&7\end{array}\right]  \left[\begin{array}{ccc}-2&4\\1&3\end{array}\right] =

Now let's find B*A

\left[\begin{array}{ccc}-2(-2)+1*1&-2*4+1*3\\3(-2)+7*1&3*4+7*3\end{array}\right] =\left[\begin{array}{ccc}5&-5\\1&23\end{array}\right]

c) They are not

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