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Novay_Z [31]
3 years ago
7

Point A is at (-2,-7) and point B is at (7,4). What is the midpoint of line segment AB?

Mathematics
1 answer:
Lyrx [107]3 years ago
4 0
Use the midpoint formula and solve. work pictured below

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Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance. For what fraction of
Kruka [31]

Answer:

Lola was in lead for \frac{6}{25} of a mile.

Step-by-step explanation:

We have been given that Lola and Brandon had a running race. They ran 3/10 of a mile. Lola was in the lead for 4/5 of the distance.

To find the fraction of a mile for which Lola was in the lead, we need to find 4/5 of 3/10 as:

\text{Fraction for which Lola was in lead}=\frac{3}{10}\times\frac{4}{5}

\text{Fraction for which Lola was in lead}=\frac{3}{5}\times\frac{2}{5}

\text{Fraction for which Lola was in lead}=\frac{3\times2}{5\times5}

\text{Fraction for which Lola was in lead}=\frac{6}{25}

Therefore, Lola was in lead for \frac{6}{25} of a mile.

7 0
3 years ago
the ratio of red marbles to blue marbles in a bag is 3:4. if there are 42 marbles in the bag, how many of the marbles are red?
AlexFokin [52]

Answer:

18

Step-by-step explanation:

Sum the parts of the ratio, 3 + 4 = 7

Divide the amount of marbles by 7 to find the value of one part of the ratio

42 ÷ 7 = 6 ← value of 1 part of the ratio, thus

red marbles = 3 × 6 = 18

8 0
3 years ago
Solve V=1/3bh for h. (1/3 is a fraction, idk if that matters.)
Vadim26 [7]

Answer:

3V/b = h

Step-by-step explanation:

Step 1: Write equation

V = 1/3bh

Step 2: Multiply both sides by 3

3V = bh

Step 3: Divide both sides by b

3V/b = h

8 0
3 years ago
Find all solutions to
BARSIC [14]

Answer:

x= 0 , \frac{1}{14} , \frac{-1}{12}

Step-by-step explanation:

Given, equation is \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x}. →→→ (1)

Now, by cubing the equation on both sides, we get

( \sqrt[3]{15x-1} + \sqrt[3]{13x+1} )³ = (4\sqrt[3]{x})³

⇒ (15x-1) + (13x+1) + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{15x-1} + \sqrt[3]{13x+1}) = 64 x.

⇒ 28x + 3×\sqrt[3]{15x-1}×\sqrt[3]{13x+1} (4\sqrt[3]{x}) = 64x.        

(since from (1),  \sqrt[3]{15x-1} + \sqrt[3]{13x+1} = 4\sqrt[3]{x})

⇒ 12× \sqrt[3]{15x-1}×\sqrt[3]{13x+1} (\sqrt[3]{x})= 36x.

⇒ 3x = \sqrt[3]{(15x-1)(13+1)(x)}.

Now, once again cubing on both sides, we get

(3x)³ = (\sqrt[3]{(15x-1)(13+1)(x)})³.

⇒ 27x³ = (15x-1)(13x+1)(x).

⇒ 27x³ = 195x³ + 2x² - x

⇒ 168x³ + 2x² - x = 0

⇒ x(168x² + 2x -1) = 0

⇒ by, solving the equation we get ,

x = 0 ; x = \frac{1}{14} ; x = \frac{-1}{12}

therefore, solution is x= 0 , \frac{1}{14} , \frac{-1}{12}

7 0
3 years ago
Josiue tosses a coin and spins the spinner at the right. What are all the possible outcomes?
vazorg [7]
The possible outcomes for the coin is 2 out of 1 since a coin has 2 sides the coin may only land on 1 side but the chances are between both sides having a 50/50 chance to land on either side.
6 0
3 years ago
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