<em><u>Hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>will</u></em><em><u> </u></em><em><u>help</u></em><em><u> </u></em><em><u>u</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>:</u></em><em><u>)</u></em>
<em><u>✌</u></em><em><u>✌</u></em><em><u>✌</u></em><em><u>✌</u></em><em><u>✌</u></em><em><u>✌</u></em>
We first write the word in math as x+3/5 = 5/7. Now we cross multiply our fractions and rewrite them with the LCD of 5 and 7. Our equation now looks like x + 21/35 = 25/35. We simplify our equation by subtracting 21/35 from both sides to get x = 4/35. 4/35 is already in lowest terms so it is our answer.
This is another one for my "impossible math question" file. All of the answer choices are wrong. (None applies.)
According to the problem statement, the length you have marked "x" in the diagram is 15 inches. If the side length of one of the pavers is "s", then the Pythagorean theorem tells us
s² + (2s)² = 15²
5s² = 225
s² = 225/5 = 45 . . . . . . the area of one square is 45 in² (not 225 in²)
Then
s = √45 = 3√5 . . . . . . . the length of one side is not 5√3
so the perimeter is
p = 4s = 4·3√5 in = 12√5 in ≈ 26.83 in . . . . not 75 inches.
The area of the 6-block L-shaped path is
total area = 6s² = 6·45 in² = 270 in² . . . . not 450 in²
And the total perimeter is 14 sides, so is
total perimeter = 14s = 14·3√5 in = 42√5 in . . . . not 60√3 in
_____
In cases like this where the answer key is incorrect, you might try asking your teacher show the class how to work the problem.
Answer:
-2
Step-by-step explanation:
Distribute
2
(
3
+
4
)
+
2
=
4
+
3
{\color{#c92786}{2(3x+4)}}+2=4+3x
2(3x+4)+2=4+3x
6
+
8
+
2
=
4
+
3
{\color{#c92786}{6x+8}}+2=4+3x
6x+8+2=4+3x
2
Add the numbers
6
+
8
+
2
=
4
+
3
6x+{\color{#c92786}{8}}+{\color{#c92786}{2}}=4+3x
6x+8+2=4+3x
6
+
1
0
=
4
+
3
6x+{\color{#c92786}{10}}=4+3x
6x+10=4+3x
3
Rearrange terms
6
+
1
0
=
4
+
3
6x+10={\color{#c92786}{4+3x}}
6x+10=4+3x
6
+
1
0
=
3
+
4
6x+10={\color{#c92786}{3x+4}}
6x+10=3x+4
4
Subtract
1
0
10
10
from both sides of the equation
6
+
1
0
=
3
+
4
6x+10=3x+4
6x+10=3x+4
6
+
1
0
−
1
0
=
3
+
4
−
1
0
6x+10{\color{#c92786}{-10}}=3x+4{\color{#c92786}{-10}}
6x+10−10=3x+4−10
5
Simplify
Subtract the numbers
Subtract the numbers
6
=
3
−
6
6x=3x-6
6x=3x−6
6
Subtract
3
3x
3x
from both sides of the equation
6
=
3
−
6
6x=3x-6
6x=3x−6
6
−
3
=
3
−
6
−
3
6x{\color{#c92786}{-3x}}=3x-6{\color{#c92786}{-3x}}
6x−3x=3x−6−3x
7
Simplify
Combine like terms
Combine like terms
3
=
−
6
3x=-6
3x=−6
8
Divide both sides of the equation by the same term
3
=
−
6
3x=-6
3x=−6
3
3
=
−
6
3
\frac{3x}{{\color{#c92786}{3}}}=\frac{-6}{{\color{#c92786}{3}}}
33x=3−6
9
Simplify
Cancel terms that are in both the numerator and denominator
Divide the numbers
=
−
2
Answer:
5.5, 9.5
Step-by-step explanation:
Let x and y be the numbers
x+y = 15
x-y = 4
Add the two equations together to eliminate y
x+y = 15
x-y = 4
------------------
2x = 19
Divide by 2
2x/2 =19/2
x = 9.5
Now find y
x+y = 15
9.5+y = 15
Subtract 9.5
x = 15-9.5
x =5.5
