All categories

2 years ago

Help pls!!!!!! Brainiest goes to first answer

Mathematics

1 answer:

Viktor [21]2 years ago

8 0

3x+1 djdjdjdjdidjdjdjfjdjdjdj

You might be interested in

What is the domain of f(x) = 1/(x-2) -3?

Ronch [10]

(negative infinity, 2] [2,infinity)

6 0

3 years ago

PLEASE HELP I ONLY NEED THIS TO GET A 100 IN HOMEWORK!!! HELP PLEASE!

DerKrebs [107]

Answer:

Step-by-step explanation:

First fraction:

Numerator:

(17/40 + 0.6 - 0.005) = 1.02

1⅕ = 1.2

(1.2 ÷ 1.02)×1.7 = 2

Denominator:

5/6 + 4/3 - 53/30

Lcm: 30

(5×5 + 4×10 - 53)/30

12/30 = 0.4

Fraction value: 2/0.4 = 5

Second fraction:

4.75 + 7.5 = 12.25

33 ÷ 33/7

33 × 7/33 = 7

12.25/7 = 1.75

1.75 ÷ 0.25 = 7

Final answer:

5 + 7 = 12

7 0

3 years ago

What’s 2 + 2? <br> A. 0<br> B. 1<br> C. 2<br> D. 4

snow_tiger [21]

Answer:

are u kidding me it's literally D --_--

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

Find all the square roots of x2 ≡ 53 (mod 77)

Nikolay [14]

Answer:

$x=\pm\sqrt{77n+53}$

Step-by-step explanation:

We have been given an equivalence equation $x^2\equiv 53\text{ (mod } 77)$ . We are asked to find all the square root of the given equivalence equation.

Upon converting our given equivalence equation into an equation, we will get:

$x^2-53=77n$

Add 53 on both sides:

$x^2-53+53=77n+53$

$x^2=77n+53$

Take square root of both sides:

$x=\pm\sqrt{77n+53}$

Therefore, the square root for our given equation would be $x=\pm\sqrt{77n+53}$ .

3 0

3 years ago

The following data set represents the age of

Julli [10]

$\huge\text{Hey there!}$

$\huge\textsf{Breaking the meaning down in simpler terms}$
$\huge\textbf{Median:}\\\large\text{is understood to be \bf the number in the center (also known as}\\\large\textbf{the middle number)}$

$\huge\textbf{Mean:}\\\large\text{is understood to be the \bf total.}$

$\huge\textsf{Formulas for each term}$

$\huge\text{Median:}\\\large\textsf{To find the median you have to put each of your numbers in your data}\\\large\textsf{set from LEAST (smallest) to GREATEST (biggest). }$

$\huge\text{Mean:}\\\mathsf{\dfrac{sum\ of\ all\ terms}{number\ of\ terms}= mean}$

$\huge\textbf{SOLVING FOR THE QUESTION}$

$\huge\textsf{Median:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textbf{Conversion: }\large\text{27, 33, 38, 41, 42, 52, 64, 68, 72}\\\\\large\textsf{Make sure it is even between both sides of the data plot.}\\\\\large\text{It seems to even on BOTH sides of \boxed{\textsf{14}} so it could possibly be your}\\\large\text{median.}$

$\huge\textsf{Mean:}\\\\\large\textbf{Original data set: }\large\text{27, 52, 64, 41, 33, 38, 42, 60, 72, 68}\\\\\large\textsf{Your equation: }\mathsf{\dfrac{27 + 52 + 64 + 41 + 33 + 38 + 42 + 60 +72 + 68}{10}}\\\\\mathsf{\dfrac{79 + 64 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{143 + 41 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{184 + 33 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{217 + 38 + 42 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{255 + 42 + 60 + 72 + 68}{10}}$

$\mathsf{\dfrac{297 + 60 + 72 + 68}{10}}\\\\\mathsf{\dfrac{357 + 72 + 68}{10}}\\\\\mathsf{\dfrac{429 + 68}{10}}\\\\\mathsf{\dfrac{497}{10}}\\\\\mathsf{\approx 49.70}\\\\\large\text{From the looks of it \boxed{\rm{\dfrac{497}{10}}}\ or \boxed{\text{49.70}} could possibly be your mean.}$

$\huge\text{Good luck on your assignment \& enjoy your day!}$

<h3>
~ $\frak{Amphitrite1040:)}$ </h3>

8 0

2 years ago