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mrs_skeptik [129]
3 years ago
5

What do you guys like about school

Physics
2 answers:
PilotLPTM [1.2K]3 years ago
8 0

Answer:

umm.....the teachers and friends

vazorg [7]3 years ago
7 0

The drama, and friends.

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A 1.94-m-diameter lead sphere has a mass of 5681 kg. A dust particle rests on the surface. What is the ratio of the gravitationa
scoundrel [369]

To develop this problem we will apply Newton's laws regarding gravitational forces, both in space and on earth. From finding this relationship, leaving the variable of the dust mass open, we will find the relationship of the forces between the two surfaces. Our values are,

\text{Diameter of the lead sphere} =  D=1.940m

\text{Mass of the lead sphere} =  m_1 = 5681kg

\text{Mass of the dust particle} = m_2

Distance between the center of lead sphere to dust particle

r = \frac{D}{2}

r = \frac{1.940m}{2}

r = 0.97m

Gravitational force of the sphere on the dust particle:

F = \frac{Gm_1m_2}{r^2}

F = \frac{(6.67*10^{-11}N\cdot m^2/kg^2)(5681kg)(m_2)}{(0.97m)^2}

F = (4.027*10^{-7} N/kg)m_2

Weight of the dust particle

W = m_2 g

W = m_2 (9.8m/s^2)

Ratio of F and W:

\frac{F}{W} = \frac{(4.07*10^{-7}N/kg) m_2)}{m_2(9.8m/s^2)}

\frac{F}{W} = 4.153*10^{-8}

Therefore the ratio is 4.153*10^{-8}

3 0
3 years ago
Which property of a substance can determine using a ph indicator
vagabundo [1.1K]

Answer:

The acidic or the basic nature of a substance can be determined using a pH indicator. If the pH indicator , shows a pH value less than 7 , the substance is acidic. Lower the pH , high is the acidic nature.

Explanation:

7 0
3 years ago
Perception is the psychological process in which sensory input is __________.
Artist 52 [7]
D
Explanation
Nothing
3 0
3 years ago
Kinetic energy is measured in joules. True or false
Mademuasel [1]

Answer:True

Explanation:

5 0
3 years ago
Read 2 more answers
An incline plane has Ф = 40.0° and μ k = 0.15. Starting from rest, how long will it take a 4.0 kg block to reach a speed of 12 m
lesya [120]
     The block on the action of two forces, the Force of Friction and the Tangential Weight. Using the Newton's Secound Law, we have:

P_{t}-Fat=ma \\ mgsen\O-mgucos\O=ma \\ a=g(sen\O-ucos\O)
 
     Using the Velocity Hourly Equation, we get:

V=V_{o}+a\Delta t \\ \Delta t= \frac{V}{a}
 
     Uniting the equations:

\Delta t=  \frac{V}{g(sen\O-ucos\O)}
 
     Entering the unknowns:

\Delta t= \frac{V}{g(sen\O-ucos\O)} \\ \Delta t= \frac{12}{10(sen40^o-0.15cos^o)}  \\ \Delta t= \frac{12}{10(0,64-0.15x0.77)}  \\ \Delta t= \frac{12}{5.27}  \\ \boxed {\Delta t=2.28s}

Obs: Approximate results

If you notice any mistake in my english, please let me know, because i am not native.

5 0
3 years ago
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