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zzz [600]
3 years ago
15

Which biological molecule contains a large amount of the element nitrogen

Physics
1 answer:
andrezito [222]3 years ago
5 0
On average, the actual protein molecule carries percentage of the atomic number 7 by weight unit. Nitrogen molecule
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An object will begin moving from rest when acted upon by which forces?
denis23 [38]

Answer:

C. The gravity acceleration is in the same direction as the force of gravity, and thus toward the center of the earth.

Explanation:

[ More info.- It doesn't affect the body when it is at the rest, and when it is in motion, it acts toward the center of the Earth and it's component is known as "Centripetal force" ]

UwU

3 0
3 years ago
Calculate the kinetic energy in joules of a 1500 kg automobile moving at 19 m/s
Svetlanka [38]
Using
KE = ½mv² = ½×1500×19×19 = 270750 joules
5 0
3 years ago
A cell membrane consists of an inner and outer wall separated by a distance of approximately 10nm. Assume that the walls act lik
Nina [5.8K]

Answer:

1 × 10⁶ N/C

Explanation:

The magnitude of the electric field between the membrane = surface density / permittivity of free space = 10 ⁻⁵C/ m² / (8.85 × 10⁻¹²N⁻¹m⁻²C²) = 1.13 × 10⁶ N/C approx 1 × 10⁶ N/C

4 0
3 years ago
Daniel and Christopher were on a plane traveling at a velocity of 200 km/hr south for 1,000 km. How long (in hours) was the plan
docker41 [41]
Answer:
5 hours

step-by-step explanation:
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3 0
3 years ago
If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positi
Alex

If a gun is sighted to hit targets that are at the same height as the gun and 85 m away at the same height, how low, as a positive number in meters, will the bullet hit if aimed directly at a target 180 m away

The muzzle velocity of the bullet is 275 m/s

Answer:

y = -1.1109 m

Explanation:

Range = \frac{v^2sin2\theta}{g}

range = 85 m

velocity = 275 m/s

g = 9.8 m/s²

85 = \frac{(275)^2sin2 \theta}{9.8}

833=(275)^2sin2\theta

833= 75625sin2\theta

0.01101 =sin2 \theta

0.005505 =sin \theta

\theta =sin^{-1}(0.005505)

\theta = 0.3154^0

If the bullet is aimed at a target 180 m, time required to travel 180 m with horizontal component will be;

t=\frac{180}{275cos0.3154}

t = 0.6546 sec

To determine, how low as a positive number in meters.

y=vyt-\frac{gt^2}{2}

y = 275 sin(0.3154)*(0.6546)- \frac{9.8*(0.6546)^2}{2}

y = 0.9909 - 2.1018

y = -1.1109 m

7 0
3 years ago
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