Answer:
2156J
Explanation:
Given parameters:
Height of lift = 10m
Mass = 22kg
Unknown:
Work done by the machine = ?
Solution:
Work done is the force applied to move a body through a certain distance.
So;
Work done = Force x distance
Here;
Work done = mass x acceleration due to gravity x height
Work done = 22 x 9.8 x 10 = 2156J
Answer:
The impuise is 7.9905 kg*m/s
Explanation:
Step one:
given data
v1= +2.63m/s
v2=-20.2m/s
mass m= 0.350kg
Step two:
From the expression for impulse
Ft= mΔv
substituting our data into the expression we have
Ft= 0.35*(-20.2-2.63)
Ft= 0.35*22.83
Ft=7.9905 kg*m/s
