(a) The total momentum of the system before the train cars collide is 1,600 kgm/s.
(b) The total momentum of the system be after the train cars collide is 1,600 kgm/s.
<h3>What is the total momentum of the car system before the collision?</h3>
The total momentum of the car system before the collision is determined by applying the formula for linear momentum.
Pi = m₁u₁ + m₂u₂
where;
- m₁ is the mass of the car on the right
- m₂ is the mass of the car on the left
- u₁ is the initial velocity of the right
- u₂ is the initial velocity of the car on the left
Let the rightward direction = positive
Let the leftward direction = negative
Pi = (600 kg x 4 m/s) + (400 kg) x (-2 m/s)
Pi = 2,400 kgm/s - 800 kgm/s
Pi = 1,600 kgm/s
Based on the law of conservation of linear momentum, the sum of the initial momentum of an isolated system is <u>equal</u> to the sum of the final momentum of the system
Pf = Pi = 1,600 kgm/s.
Learn more about conservation of linear momentum here: brainly.com/question/7538238
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Answer:
The velocity of the pin is opposite its acceleration on the way up.
(d) option is correct.
Explanation:
when the juggler throws a bowling pin straight in the air, the acceleration working on the pin is in the downward direction due to the gravitational force of the earth.
According to Newton's Universal Law of Gravitation
''The gravitational force is a force that attracts any objects with mass''
Answer:
The amount of potential energy that was initially stored in the spring is 88.8 J.
Explanation:
Given that,
Mass of block = 1.60 kg
Angle = 30.0°
Distance = 6.55 m
Speed = 7.50 m/s
Coefficient of kinetic friction = 0.50
We need to calculate the amount of potential energy
Using formula of conservation of energy between point A and B



Put the value into the formula


Hence, The amount of potential energy that was initially stored in the spring is 88.8 J.