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Novosadov [1.4K]
3 years ago
12

X2 + 45x = -200 Using the quadratic formual and the discirimnat

Mathematics
1 answer:
dybincka [34]3 years ago
7 0

Answer:

Positive discriminant = 2 real solution

x= -5,-40

Step-by-step explanation:

The discriminant is used to see how many solutions an equation has. If it is negative, the equation has no real solutions, if =0 the equation has 1, and if it is positive, the equation has two real solutions.

The discriminant is the part of the quadratic formula inside the square root:

b^{2}-4ac

Every quadratic formula has the structure:

ax^{2} +bx+c=0

So first, in order to meet this structure we need to add 200 to both sides so the equation is equal to 0. This gives us:

x^{2} +45x+200=0

Our a=1, b=45 and c=200

Now we can substitute these values into the discriminant:

(45)^{2} -4(1)(200)

Solve:

2025-800=1225

The discriminant is a positive number which means this equation will have 2 real solution. Now we just need to plug in our values into the quadratic formula to solve this equation. Quadratic formula:

x=\frac{-+/-\sqrt{b^{2}-4ac} }{2a} \\x=\frac{-45+/-\sqrt{1225} }{2}

(Same discriminant value)

x=\frac{-45+/-35}{2}

Now to find the two solutions, we use both signs in the equation. Solution 1:

x=\frac{-45+35}{2}

x=\frac{-10}{2}=-5

Our first solution is -5, now for the second:

x=\frac{-45-35}{2}\\\\ x=\frac{-80}{2}=-40

The two solution to this equation are -5 and -40.

Hope this helped!

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Find the constant $a$ such that\[(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28.\]
Colt1911 [192]

The value of constant a is -5

Further explanation:

We will use the comparison of co-efficient method for finding the value of a

So,

Given

(x^2 - 3x + 4)(2x^2 +ax + 7)\\= x^2((2x^2 +ax + 7)-3x((2x^2 +ax + 7)+4(2x^2 +ax + 7)\\= 2x^4+ax^3+7x^2-6x^3-3ax^2-21x+8x^2+4ax+28\\Combining\ alike\ terms\\=2x^4+ax^3-6x^3+7x^2-3ax^2+8x^2-21x+4ax+28\\= 2x^4 +(a-6)x^3+(15-3a)x^2-(21-4a)x+28\\

As it is given that

(x^2 - 3x + 4)(2x^2 +ax + 7) = 2x^4 -11x^3 +30x^2 -41x +28

In this case, co-efficient of variables will be equal, so we can compare the coefficients of x^3, x^2 or x

Comparing coefficient of x^3

a-6 = -11\\a = -11+6\\a = -5

So the value of constant a is -5

Keywords: Polynomials, factorization

Learn more about factorization at:

  • brainly.com/question/1414350
  • brainly.com/question/1430645

#LearnwithBrainly

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