Since those two triangles are similar by AA
then use proportions to get "x"
thus
![\bf \cfrac{x+4}{16}=\cfrac{x-08}{WU}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7Bx%2B4%7D%7B16%7D%3D%5Ccfrac%7Bx-08%7D%7BWU%7D)
hmmm wait just a second? what the dickens is WU anyway?
well, let's take a look at the triangle on the right-side
is a right-triangle, has a 90° angle
so, just use the pythagorean theorem to get WU
![\bf c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b\qquad \begin{cases} c=WY\\ a=UY\\ b=WU \end{cases}\\\\ -----------------------------\\\\ \sqrt{(WY)^2-(UY)^2}=WU](https://tex.z-dn.net/?f=%5Cbf%20c%5E2%3Da%5E2%2Bb%5E2%5Cimplies%20%5Csqrt%7Bc%5E2-a%5E2%7D%3Db%5Cqquad%20%0A%5Cbegin%7Bcases%7D%0Ac%3DWY%5C%5C%0Aa%3DUY%5C%5C%0Ab%3DWU%0A%5Cend%7Bcases%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%5Csqrt%7B%28WY%29%5E2-%28UY%29%5E2%7D%3DWU)
which will give you
![\bf \cfrac{x+4}{16}=\cfrac{x-08}{\boxed{\sqrt{(WY)^2-(UY)^2}}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ccfrac%7Bx%2B4%7D%7B16%7D%3D%5Ccfrac%7Bx-08%7D%7B%5Cboxed%7B%5Csqrt%7B%28WY%29%5E2-%28UY%29%5E2%7D%7D%7D)
solve for "x"
Answer:
all you need to do is fine the difference of the numbers
Step-by-step explanation:
Answer:
0.44
Step-by-step explanation:
im pretty sure it is 0.44 because of the division.
Answer:
hytgfdsawedrftgyhujyhgtrfdewsaswdefrgthyjuijyhtgrfedrftgyhujhtg
Step-by-step explanation:
gfvbhnnnffbgfrerrrrrrrrrrrrrrftgfdcfsvgfffffffffffffffffffffffff
gfvvvvvvvvvv
gfv
gfv
g