3 years ago

PLEASE HELP urgent math questions

Mathematics

1 answer:

Phoenix [80]3 years ago

7 0

Answer:B

Step-by-step explanation:

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ioda

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3 years ago

Humood's house is (-5,7)

grin007 [14]

The distance from Humood's house to the school is 500m

<h3>How to determine the distance from Humood's house to the school?</h3>

The given parameters are:

Humood's house is (-5,7)

The school is (3,1)

The distance between both points is calculated using

$d = \sqrt{(x_2- x_1)^2 + (y_2 - y_1)^2$

Substitute the known values in the above equation

$d = \sqrt{(-5 - 3)^2 + (7 - 1)^2$

Evaluate

d = 10

Each unit in the graph is 50m.

So, we have

Distance =10 * 50m

Evaluate the product

Distance = 500m

Hence, the distance from Humood's house to the school is 500m

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brainly.com/question/1872885

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2 years ago

Claire is cycling at a speed of 12 miles per hour. Han is cycling at a speed of 8 miles per hour. If they start at the same posi

larisa [96]

Answer:

45 minutes is 3/4 of an hour, so find 3/4 of 12.

Divide 12 by 4 to get 1/4 of 12. That is 3.

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Answer:

-4/5

Step-by-step explanation:

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