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3 years ago

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Sydney and Tom each count the number of steps it takes for them to walk to school. They each count a 4 digit number of steps. To

tal number of steps is also 4 digit. What is the greatest possible digit in the thousands place for Sydney's or Tom's steps?

1 answer:

lesantik [10]3 years ago

7 0

Answer:

8

Step-by-step explanation:

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AleksAgata [21]

Answer:

The answer is -- all integers from 10 to 50, inclusive

Hope I Helped.

(I am sure of the answer, I have completed the test.)

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3 years ago

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ace landscape buys 100 shovels for $15 each. ace sells all 100 shovels at $29.99. what is his profit?

Delicious77 [7]

To work out the profit, firstly, you have to work out the cost of buying them, which is $15 multiplied by 100, which is $1500. You then have to work out what he sold them all at, which is $29.99 multiplied by 100, which is $2999. You then have to subtract $1500 from $2999, giving you $1499. Therefore, Ace made $1499 in profit. Hope this helps :)

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I need help writing the first 5 terms of the sequence!

Angelina_Jolie [31]

The first five terms of the sequence are 1, 4, 7, 10, 13.

Solution:

Given data:

$a_{1}=1$

$a_{n}=a_{n-1}+3$

General term of the arithmetic sequence.

$a_{n}=a_{n-1}+d$ , where d is the common difference.

d = 3

$a_{n}=a_{n-1}+3$

Put n = 2 in $a_{n}=a_{n-1}+3$ , we get

$a_{2}=a_1+3$

$a_{2}=1+3$

$a_2=4$

Put n = 3 in $a_{n}=a_{n-1}+3$ , we get

$a_{3}=a_2+3$

$a_{3}=4+3$

$a_3=7$

Put n = 4 in $a_{n}=a_{n-1}+3$ , we get

$a_{4}=a_3+3$

$a_{4}=7+3$

$a_4=10$

Put n = 5 in $a_{n}=a_{n-1}+3$ , we get

$a_{5}=a_4+3$

$a_{5}=10+3$

$a_5=13$

The first five terms of the sequence are 1, 4, 7, 10, 13.

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3 years ago

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MrRissso [65]

Answer:

What is the question?

Step-by-step explanation:

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3 years ago

How do i evaluate (7 to the power of 2)to the power of 3)=7 to the power of 5

kakasveta [241]

Step-by-step explanation:

$(7^2)^3=7^5\qquad\bold{FALSE}\\\\\text{because}\\\\7^2=7\cdot7\\\\(7^2)^3=(7\cdot7)^3=(7\cdot7)\cdot(7\cdot7)\cdot(7\cdot7)=\underbrace{7\cdot7\cdot7\cdot7\cdot7\cdot7}_6=7^6\\\\\text{or use}\ (a^n)^m=a^{nm}\\\\(7^2)^3=7^{2\cdot3}=7^6$

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