Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r = 
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer:
x=2/5 or
x=0.4
Step-by-step explanation:
Judging by the problem you want me to use substitute method
Since why equals 1/2x-1 you
Do 2(1/2x-1)= x-2
You multiple by 2 cause there’s two on the top for y. So the problem is now 4x-x-2
Combine like terms 3x+2=14
Subtract two on both sides
3x=12
X=4
Go back to the bottom since u know x now do y= 4.1/2-1 solve to get one
Y=1 so your answer is (4,1)
Step-by-step explanation:
step 1. ABCD is an isosceles trapezoid because AD and BC are parallel, AB and CD are congruent
step 2. x = 56° (definition of an isosceles trapezoid)
step 3. x + y + z + 56 = 360 (definition of a quadrilateral)
step 4. y = z (definition of an isosceles trapezoid)
step 5. 56 + 2y + 56 = 360
step 6. 2y = 248
step 7. y = 124°, z = 124°.
Answer:
i believe the answer is D
Step-by-step explanation:
im not entirely sure but that's what i got.
