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Kitty [74]
4 years ago
15

HELP PLEASE -ILL GIVE BRILLIANT-

Mathematics
2 answers:
Usimov [2.4K]4 years ago
6 0

Answer:

The cube will fit on the shelf.

Explanation:

If the volume is 10 cubic feet, then the height is around 2.1-2.2 feet high. One foot is 12 inches, so the height in inches is around 25.2-26.4 which is less than 30 inches.

inessss [21]4 years ago
3 0

Answer:

Yes

Step-by-step explanation:

First, find the side length of the cube. The volume of a cube is denoted by: V = s * s * s, where s is the side length. We don't know the side length here, but we do know the volume, so plug that in:

10 = s * s * s

s = ∛10 = 2.2 ft

Convert this to inches by multiplying by 12:

2.2 * 12 = 26.4 inches

Thus, since 26.4 < 30, the cube can fit on the shelf.

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Answer:

D

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HELP ASAP 10 POINTS AND BRAINLIEST
LUCKY_DIMON [66]

Answer:

135

Step-by-step explanation:

The area is given by

A = bh  where b is the base and h is the height

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7 0
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Read 2 more answers
Eli claims that the product of and is . Which explains whether Eli is correct?
Shalnov [3]

Answer: last option.

Step-by-step explanation:

According to the Product of powers property, you have:

a^n*a^m=a^{(n+m)}

As you can see, when you can add the exponents when you have powers with equal base.

Then,  6^5  and 5^{-3} do not have the same base, therefore, the exponents can't be added.

Therefore, Eli is incorrect, because he added the exponents even though the bases are not the same.

6 0
4 years ago
6^3 x 2^6/2^3<br> Which expressions are equal to 2^6 x 3^8<br> 2^3 . 3^3<br> 12^6<br> 12^3
pav-90 [236]

Answer:

None?

Step-by-step explanation:

Idk what the 6^3 x 2^6/2^3 means but 2^6 x 3^8 = 419904 and none of the other choices match this sorry.

3 0
4 years ago
The width of a rectangle is only 15% of its length. If the perimeter of the rectangle is 46, what is the length
sveta [45]

Answer:

20 units

Step-by-step explanation:

Let the length be x. According to the question,

  • Length = x
  • Width = 15% of the length

➝ Width = 15% of the length

➝ Width = 15/100x

➝ Width = 3/20x

We have the perimeter of the rectangle that is 46 units.

\longrightarrow \sf {Perimeter_{(Rec.)} = 2(L + W) } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup x + \dfrac{3}{20}x \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{20x + 3x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {46= 2\Bigg \lgroup \dfrac{23x}{20} \Bigg \rgroup } \\

\longrightarrow \sf {\dfrac{46}{2}=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23=  \dfrac{23x}{20}} \\

\longrightarrow \sf {23 \times 20 = 23x} \\

\longrightarrow \sf {460= 23x} \\

\longrightarrow \sf {\cancel{\dfrac{460}{23}} = x} \\

\longrightarrow \underline{\boxed{ \bf {20\; units = x}}} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>rectang</u><u>le</u><u> </u><u>is</u><u> </u><u>2</u><u>0</u><u> </u><u>units</u><u>.</u>

5 0
4 years ago
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