Answer:
1: 11982.79
2: 12136.31
4: 12216.09
12: 12270.46
365: 12297.10
Step-by-step explanation:
The compound interest formula is A=P*(1+r/n)^nt
P=principal amount
r=rate
n=number of compounds per period
t=number of periods
In this situation, the principal amount is 5,000=P. The rate is 6%, so r=0.06. n is equal to the top number in the table. And this is 15 years, so t=15.
For 1, it would be A=5,000*(1+.06/1)^1*15, or A=5,000(1.06^15), or 11982.79.
For 2, it would be 5,000*(1+.06/2)^2*15, or 5,000*(1.03^30), or 12136.31.
And so forth. Good luck
the gym teacher has lots of wood
Step-by-step Sorry I got this from the book and it’s the real answer
The correct answer is choice A. Qualitative data is data that is collected based on a quality or a characteristic. These type of data will not involve numbers or measurements, but descriptive words.
You can easily do just one step to get the value of x.
x + 9 =24 subtract 9 from both sides
x + 9 - 9 = 24 - 9
Simplify:
x = 15I hope I helped
you.
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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