Answer:
Roberto is correct because 15/16 x 4/5 = 3/4.
Roberto's solution to the division problem is correct, but
there are no true statements on your list of choices.
Answer:
No because even though you aren't actually picking the exact people yo do and don't wanna survey but your only surveying those who buy hot lunches when in order to get accurate data, you have to survey everyone who bought hot and cold lunches from the school cafeteria.
Answer:
a) For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
b) For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Step-by-step explanation:
Previous concepts
The t distribution (Student’s t-distribution) is a "probability distribution that is used to estimate population parameters when the sample size is small (n<30) or when the population variance is unknown".
The shape of the t distribution is determined by its degrees of freedom and when the degrees of freedom increase the t distirbution becomes a normal distribution approximately.
The degrees of freedom represent "the number of independent observations in a set of data. For example if we estimate a mean score from a single sample, the number of independent observations would be equal to the sample size minus one."
Solution to the problem
Part a
For the 90% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =3. And we can use the folloiwng excel code: "=T.INV(0.05,3)" and we got:
Part b
For the 99% confidence interval the value of
and
, with that value we can find the quantile required for the interval in the t distribution with df =106. And we can use the folloiwng excel code: "=T.INV(0.005,106)" and we got:
Answer:
sedan = 26 miles/gallon
truck = 17 miles/gallon
Step-by-step explanation:
try to write the text in mathematical format as a system of equations
t=truck s=sedan

first equation can be written as
t= (181-5s)/3
we can use it in the second equation and rewrite it as
7[(181-5s)/3]+6s = 275
7(181/3 -5/3s) + 6s = 275
1267/3 - 35/3s + 6s = 275
-35/3s + 18/3s = 275-1267/3
-35/3s + 18/3s = 825/3 - 1267/3
-35s + 18s = 825 -1267
-17s = -442 s = 442/17 = 26 sedan has an average of 26 miles/gallon
we use this value of s in the first equation
3t + 5*26=181 3t=181-130 t= 51/3 = 17 truck has an average of 17 miles/gallon
1 i think? sry if im wrong