Aidan used
170 * 0.37 = $62.90
it costed:
60 * 0.37 = $22.20
hence change in expense will be:
62.90 - 22.20 = <span>$40.70</span>
Answer:
$ 2,600 was invested at 4% and $ 3,600 was invested at 9%.
Step-by-step explanation:
Given that in investing $ 6,200 of a couple's money, a financial planner put some of it into a savings account paying 4% annual simple interest, and the rest was invested in a riskier mini-mall development plan paying 9% annual simple interest, and the combined interest earned for the first year was $ 428, to determine how much money was invested at each rate, the following calculation must be performed:
3000 x 0.04 + 3200 x 0.09 = 408
2500 x 0.04 + 3700 x 0.09 = 433
2600 x 0.04 + 3600 x 0.09 = 428
Therefore, $ 2,600 was invested at 4% and $ 3,600 was invested at 9%.
Not quite understand the question. We assume that the issue of ratios of numbers of 800 and 8000.
Then 800 is one-tenth of the 8,000 800 other words is 10% of 8000.
Conversely, 8000 it ten times at 800 and 1000% of 800.
For this case we must add the terms of the following expression:

It is noted that the terms are similar, so we can add:
We take common factor 

We add the terms within the parenthesis:

finally we have:

Answer:
