All categories

3 years ago

How do i solve this

Mathematics

1 answer:

OverLord2011 [107]3 years ago

3 0

I hope this is right, but try this !! someone confirm if possible too

You might be interested in

Can anyone explain to me how I should go about figuring this out?

docker41 [41]

Answer:

First paragraph of being a bit of an error on ep of being a bit more than

5 0

3 years ago

Solve using the box method

Lena [83]

$\huge\text{Hey there!}$

$\large\text{Just SIMPLIFY the given EQUATION or find the DIFFERENCE}\\\large\text{OF the SQUARES... Here is the formula: }\mathsf{\bf a^2 - b^2 =(a+b)(a-b)}$

$\large\text{Equation: }\mathsf{\dfrac{(4x^2-9)}{(2x + 3)}}$

$\large\text{Rewrite }\mathsf{ 4x^9 - 9}\large\text{ in the formation of }\mathsf{a^2 - b^2}\large\text{ whereas}\mathsf{a = 2x \ \&\ b = 3.}$

$\large\text{Equation: }\mathsf{\dfrac{(2x)^2-3^2}{2x + 3}}$

$\large\text{This is where you try to do the DIFFERENCE OF its SQUARES}$

$\mathsf{\dfrac{(2x + 3)(2x - 3)}{2x + 3}}$

$\large\text{CANCEL out: }\mathsf{(2x + 3)\ - (2x +3)}\large\text{ because it gives you 0}$

$\large\text{This leaves us with }\mathsf{\bf 2x - 3}\large\text{ as your POSSIBLE ANSWER}$

$\boxed{\boxed{\large\text{Answer: \huge \bf 2x - 3}}}\huge\checkmark$

$\text{Good luck on your assignment and enjoy your day!}$

~ $\frak{Amphitrite1040:)}$

$\large\text{Note: There is/are many ways to solve for equations like this.... this was just}\\\large\text{the quickest and easiest way to understand it!}$

3 0

3 years ago

If you have two apples and you take 1 apple, how many do you have? Easy questions!Free points!

Cloud [144]

Answer:

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Suppose you were to draw all possible samples of size 36 from a large population with a mean of 650 and a standard deviation of

Lady_Fox [76]

Answer:

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

Step-by-step explanation:

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 650 and a standard deviation of 24.

This means that $\mu = 650, \sigma = 24$ .

Sample of 36:

This means that $n = 36, s = \frac{24}{\sqrt{36}} = 4$

What is the shape of the sampling distribution you would expect to produce?

By the Central Limit Theorem, it is approximately normal with mean 650 and standard deviation 4.

7 0

3 years ago

The Sanchez family drove 132 miles in 3 hours before lunch. Then they drove 240 miles in 5 hours after lunch.

lilavasa [31]

The formula for speed is the total distance traveled over time. We shall calculate the 2 speeds individually- before and after lunch. Afterwhich, we shall add them together and divide by 2 to get the average.
Before lunch s = 132 mi / 3 hr = 44 mi/hr
After lunch s = 240 mi / 5 hr = 48 mi/hr

Ave s= 48 + 44 / 2
Ave s= 46 mi/hr

Therefore the correct answer is A.

3 0

3 years ago