Ask question

Ask question

All categories

3 years ago

5

Question 4 of 11

1 answer:

MAVERICK [17]3 years ago

7 0

This would be A True, hope this helps !

You might be interested in

Multiple Representations On a? map, 4 inches equals 120 miles. The distance that a family travels is 4.5 inches on the map. Repr

kenny6666 [7]

Okay the scale for this equation is each inch equals 30 miles. SO to get how many miles 4.5 inches equals to, we have to multiply 30 by 4.5, and the answer we get is 135.

I hope this helps!

5 0

3 years ago

Montoya Construction needs to borrow $375,000 to build a road to install utilities in a small subdivision. It borrows the funds

MissTica

Step 1

Given;

$\begin{gathered} \text{Principal(p)= \$375000} \\ \text{First rate = 8\%=}\frac{8}{100}=0.08 \\ \text{Second rate = 20\%= }\frac{20}{100}=0.2 \\ \text{Time}=\frac{90}{365}=\frac{18}{73} \end{gathered}$

Required; To find the difference in interest between the two periods.

Step 2

State the formula for simple interest

$A=P(1+rt)$

Step 3

Find the interest when the rate is 8%

$\begin{gathered} A=375000(1+(0.08\times\frac{18}{73}) \\ A=375000(1+\frac{36}{1825}) \\ A=\text{\$}382397.26 \end{gathered}$

Therefore the interest is given as;

$A-P=382397.26-375000=\text{\$}7397.26$

Step 4

Find the interest in 1980 with a 20% rate

$\begin{gathered} A=375000(1+(0.2\times\frac{18}{73}) \\ A=\text{\$}393493.15 \end{gathered}$

The interest is given as;

$A-p=393493.15-375000=\text{\$}18493.15\text{ }$

Step 5

Find the difference in interest between the two rates.

$\text{\$}18493.15-\text{\$}7397.26=\text{\$}11095.89$

Hence, the difference in interest between the two rates = $11095.89

4 0

1 year ago

4/3 to the third power as a simplified fraction

zloy xaker [14]

Answer:

64/27

Step-by-step explanation:

(4/3)^3=(4/3)*(4/3)*(4/3)=64/27

6 0

3 years ago

Read 2 more answers

12. A shoebox has a volume of 456 cm3 and a mass of 114 g. What is its<br> density?

victus00 [196]

Answer:

114.0g/538.5cm^3=0.2117 glcm^3

Step-by-step explanation:

8 0

2 years ago

In a random sample of 400 residents of Boston, 320 residents indicated that they voted for Obama in the last presidential electi

coldgirl [10]

Answer:

C.I = 0.7608 ≤ p ≤ 0.8392

Step-by-step explanation:

Given that:

Let consider a random sample n = 400 candidates where 320 residents indicated that they voted for Obama

probability $\hat p = \dfrac{320}{400}$

= 0.8

Level of significance ∝ = 100 -95%

= 5%

= 0.05

The objective is to develop a 95% confidence interval estimate for the proportion of all Boston residents who voted for Obama.

The confidence internal can be computed as:

$=\hat p \pm Z_{\alpha/2} \sqrt{\dfrac{ p(1-p)}{n } }$

where;

$Z_{0.05/2}$ = $Z_{0.025}$ = 1.960

SO;

$=0.8 \pm 1.960 \sqrt{\dfrac{ 0.8(1-0.8)}{400 } }$

$=0.8 \pm 1.960 \sqrt{\dfrac{ 0.8(0.2)}{400 } }$

$=0.8 \pm 1.960 \sqrt{\dfrac{ 0.16}{400 } }$

$=0.8 \pm 1.960 \sqrt{4 \times 10^{-4}}$

$=0.8 \pm 1.960 \times 0.02}$

$=0.8 \pm 0.0392$

= 0.8 - 0.0392 OR 0.8 + 0.0392

= 0.7608 OR 0.8392

Thus; C.I = 0.7608 ≤ p ≤ 0.8392

3 0

3 years ago