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3 years ago

Someone please help me find the value of a and b, pretty sure my answers are wrong

Mathematics

1 answer:

Zanzabum3 years ago

8 0

Answer:

your answers are correct

Step-by-step explanation:

since all the interior angles of a triangle add up to 180 this problem is correct.

two congruent legs of a triangle means the triangle is isosceles. An isosceles triangle has base angles that measure the same, therefore a is 52.

To find b, do 180 minus the two base angles, 52, to find the solution.

$180-52-52 = 76$

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stira [4]

Answer:

145

Step-by-step explanation:

m<4 and m<3 would equal 90 so subtract 55 from 90 and you get 35 for m<3 so you subtract 35 from 180 and you get 145

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Step-by-step explanation:

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3 years ago

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3 years ago

Read 2 more answers

The volume of a rectangular prism is 2x^3 - 6x^2 + 8x , and the volume of a cube is 27x^3. What is the total volume of the prism

AleksAgata [21]

Answer:

$\displaystyle V_{P + C} = 29x^3 - 6x^2 + 8x$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

Identify.

$\displaystyle V_P = 2x^3 - 6x^2 + 8x$

$\displaystyle V_C = 27x^3$

Step 2: Find Combined Volume

[Set up] Add: $\displaystyle V_P + V_C = V_{P + C}$
Substitute in variables: $\displaystyle V_{P + C} = 27x^3 + 2x^3 - 6x^2 + 8x$
Combine like terms: $\displaystyle V_{P + C} = 29x^3 - 6x^2 + 8x$

8 0

2 years ago

The frequency of the musical note C4 is about 261.63 Hz. What is the frequency of the note a perfect fifth below C4?

kolbaska11 [484]

Answer:

The frequency of the note a perfect fifth below C4 is;

B- 174.42 Hz

Step-by-step explanation:

Here we note that to get the "perfect fifth" of a musical note we have to play a not that is either 1.5 above or 1.5 below the note to which we reference. Therefore to get the frequency of the note a perfect fifth below C4 which is about 261.63 Hz, we have

1.5 × Frequency of note Y = Frequency of C4

1.5 × Y = 261.63

Therefore, Y = 261.63/1.5 = 174.42 Hz.

6 0

2 years ago