Answer:
The number of cats at the shelter on Friday was 20.
Step-by-step explanation:
Hi there!
Let "x" be the number of cats and "y" the number of dogs.
The shelter spends $2 per cat and $7 per dog. If the total expenses on Friday was $82, then, two times the number of cats plus seven times the number of dogs is equal to 82:
2x + 7y = 82
We also know that the total number of cats and dogs was 26. Then, the number of cats plus the number of dogs is equal to 26:
x + y = 26
Let´s solve this equation for y and replace it in the first equation
y = 26 - x
Then:
2x + 7(26 - x) = 82
Apply distributive property:
2x + 182 - 7x = 82
Subtract 182 to both sides of the equation:
-5x = -100
divide both sides of the equation by -5
x = 20
The number of cats at the shelter on Friday was 20.
Have a nice day!
Answer:
Follows are the solution to this question:
Step-by-step explanation:
In point A:
The two-point C and y is given, where C is the scale drawing lengths and y is the actual mural lengths so, the formed equation is:
In point C
:
Using the value of the scale:
let 1 feet: 20 feet
therefore the equation is:
The size of c will be the length of:
The diagram c scale width will be:
Just count the units and that should give you 7 units.
Hello!
Let's write some important information contained in the exercise:
• hotdogs: $2.59 (,x,)
,
• hamburgers: $5.29 (,y,)
He needs 11 packages. Let's write it:
• x + y = 11
He spent a total of $39.29. We can write it as:
• 2.59x + 5.29y = 39.29
Now, let's solve these two equations as a linear system:
First, let's isolate x in equation A:
Now, we will replace where's x by 11-y in equation B:
As I called the hamburgers as 'y', we know that he bought 4 packages of hamburgers.
A.)
Z = kx/y where k is a constant.
32 = 16k/4
k = 128/16
k = 8
z = 8x/y
b.)
Z = 8(21)/6
Z = 28
c.)
4 = 8x/48
x = 192/8
x = 24