Answer:
x=-2 x=1
Step-by-step explanation:
16x2 + 10x – 27 = -6x + 5
Add 6x to each side
16x^2+6x + 10x – 27 = -6x+6x + 5
16x^2 +16x -27 = 5
Subtract 5 from each side
16x^2 + 16x – 27-5 = 5 - 5
16x^2 +16x -32 = 0
Factor out 16
16 (x^2 +x-2)=0
Factor
16 (x+2) (x-1) =0
Using the zero product property
(x+2) =0 x-1=0
x=-2 x=1
Answer:
2.66 and 4.34
Step-by-step explanation:
To evaluate, substitute the values of y and solve.
So, when y =-2
0.67y + 4 = -1.34 + 4 = 2.66
And when y = 2
0.67y + 4 = 1.34 + 4 = 4.34
Hope this helps.
I use the sin rule to find the area
A=(1/2)a*b*sin(∡ab)
1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]
we know that
A=5√3
BC=4
AB=5
then
sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°
now i use the the Law of Cosines
c2 = a2 + b2 − 2ab cos(C)
AC²=AB²+BC²-2AB*BC*cos (∡B)
AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21
AC=√21= 4.58 cms
the answer part 1) is 4.58 cms
2) we know that
a/sinA=b/sin B=c/sinC
and
∡K=α
∡M=β
ME=b
then
b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))
KE=b*sin(β)/sin(α)
A=(1/2)*(ME)*(KE)*sin(180-(α+β))
sin(180-(α+β))=sin(α+β)
A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
KE/sin(β)=KM/sin(180-(α+β))
KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)
the answers part 2) areside KE=b*sin(β)/sin(α)side KM=(KE/sin(β))*sin(α+β)Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)
Divide 30 by 10. 30mph/10seconds = 3mph/seconds
8 percent. The answer to 4$is what percent of 50$ is 8%
