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Setler [38]
4 years ago
10

For the following question, what is the value of x to the nearest tenth?

Mathematics
1 answer:
maria [59]4 years ago
7 0

Answer: 6.6

Just took the quiz.

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The spoke of wheel reaches from the center of the wheel to its rim if the circumstance of the wheel is 48 inches, how long is ea
user100 [1]

Answer:

7.6 in

Step-by-step explanation:

c = 2πr       Divide each side by 2π

r = C/2π     Insert values

r = 48/(2×3.14)

r = 48/6.28

r = 7.6 in

6 0
4 years ago
A company that produces an expensive stereo component is considering offering a warranty on the component. Suppose the populatio
Llana [10]

Answer:

Warranty of 66 months.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 84, \sigma = 9

If the company wants no more than 2% of the components to wear out before they reach the warranty date, what number of months should be used for the warranty?

Only the lowest 2% will be replaced, so the warranty is the value of X when Z has a pvalue of 0.02. So it is X when Z = -2.055.

Z = \frac{X - \mu}{\sigma}

-2.055 = \frac{X - 84}{9}

X - 84 = -2.055*9

X = 65.5

Warranty of 66 months.

5 0
3 years ago
In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co
sukhopar [10]

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

Education College = 30%

Calculated

Business College = 90/300= 9/30= 0.3 or 30%

Arts College= 120/300= 12/30= 2/5= 0.4 or 40%

Education College= 90/300= 9/30 = 0.3 or 30%

First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= \sqrt{npq\\}

Business College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.4*0.6*300}=  8.49

Education College

Mean = np =300*0.3= 90

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Now calculating the previous means with the same number of students

Business College

Mean = np =300*0.35= 105

Arts College

Mean = np =300*0.35= 105

Education College:

Mean = np =300*0.3= 90

Now formulate the null and alternative hypothesis

Business College

90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90     U1: mean ≠ 90

From these we conclude that the  proportions have not changed significantly meaning that it falls outside the critical region.

8 0
4 years ago
Find the greatest common factor of 11m^3 and 13m^2.<br> Help!!!
LUCKY_DIMON [66]
The greatest common factor of 11m^3 and 13m^2 is m^2.  11 and 13 don't really have a greatest common factor (they're both prime numbers), and m^2 goes into each of them.
4 0
4 years ago
TH
V125BC [204]
80 minutes because 8•10=80
8 0
4 years ago
Read 2 more answers
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