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sammy [17]
3 years ago
9

Solve the equation below for x. cx-4=7 PLZ ANSWER SOON

Mathematics
2 answers:
kiruha [24]3 years ago
6 0
Cx-4=7

add 4 on both sides

cx=11

divide c on both sides

x = \frac{11}{c}
Furkat [3]3 years ago
3 0

Answer:

x=\frac{11}{c}

Step-by-step explanation:

We have been given the equation cx-4=7

We have to eliminate 4 from the left hand side of the equation. Since, 4 is in subtraction hence, add 4 to both sides to eliminate 4.

cx-4+4=7+4\\\\cx=11

Now, we have to eliminate c. Since, c is in multiplication with x hence, divide both sides by c

\frac{cx}{c}=\frac{11}{c}\\\\x=\frac{11}{c}

Therefore, the value of x is x=\frac{11}{c}

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Answer:

The salary after four consecutive increase = $ 46794.34

Step-by-step explanation:

According to question,

salary of MR. John = $ 40000 per year

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Let the salary after four consecutive pay increase = x

So, X = 40000 (1 +\frac{4}{100})^4

Or, X = 40000 (\frac{26}{25})^4

Or, X = 46794.34

Hence the salary increase after four consecutive pay increase at 4% = $46794.34  Answer

3 0
3 years ago
Could 1.5, 2.5, 3.5 and 6, 10, 12 be the corresponding sides of two similar triangles
boyakko [2]

Answer:

No

Step-by-step explanation:

If the ratios of the corresponding sides are equal then they would be the sides of 2 similar triangles.

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\frac{12}{3.5} ≠ 4

Thus the sides are not the corresponding sides of similar triangles.

4 0
3 years ago
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Jet001 [13]
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3 0
3 years ago
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timofeeve [1]

Answer:

4.

Step-by-step explanation:

(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α

But sec^2  α = 1 + tan^2 α so

sec^2 α - tan^2α  = 1 + tan^2 α - tan^2α

= 1

so 1 =  (sec α - tan α)(sec α + tan α) = 1/4 * x     where x  is sec α + tan α

1/4 * x = 1

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6 0
3 years ago
The perimeter of a rectangle is 40 cm. The length is 14 cm. Let x = width of the rectangle. Ravi says he can find the width usin
Usimov [2.4K]

Answer:

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Step-by-step explanation:

We have the equation

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Therefore, the most helpful first step for solving Ravi's equation is: Divide both sides by 2

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3 years ago
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