Answer:
<h3>No.</h3>
Step-by-step explanation:
The sides would be unbalanced. To get the sides of a triangle, you have to add up the first two sides. The two sides combined usually have to be less than or equal to 15 to be considered "balanced". 22 is greater than 15, so that would leave you with an unbalanced triangle, sometimes considered degenerate. A degenerate triangle is a flat triangle that almost looks like a line. The triangle's vertices all lie on the same line, which makes it look very flat. That's why degenerate triangles are rarely considered "balanced" in regards to unit measures. So, given this is an unbalanced triangle, the answer to your question would be no.
Hope this helps!
Slope formula:
M= y2-y1
———
X2-x1
Answer:
Step-by-step explanation:
2 cos x + √ 2 = 0
2 cos x = -√ 2
cos x = -√ 2 / 2
x = arcCos( -√ 2 / 2 )
so to solve we have to use "co-terminal " angles .. do you know what I'm saying? do you understand the words coming out of my mouth :DDDDD OKay back to math and not movie lines .. :P
x = arcCos( √ 2 / 2 )
x = 45 °
now find the "co terminal" angle that is on 45 ° but in the correct quadrant... since the -√ 2 is negative.. we now that we go down the y axis.. but also positive on the x axis.. soooo.. that put the angle in the 4th quadrant... so this is an angle of 315° if we go in the CCW ( counter clock wise ) direction but it's also -45° in the CW (clock wise ) direction
below is the table to remember the trig special angles
notice how it's 1,2,3,4 .. so it's super easy to remember.. the trig books don't show you this "trick" :P
copy and paste this to your computer some where handy
Sin(0) = 0/2 =0
Sin(30)=
/2 = 1/2
Sing(45) =
/2 =
/2
Sin(60)=
/2 =
/2
Sin(90)=
/2 = 1
Cos is exactly the same but counts backwards from 90°
Cos(90) = 0/2 = 0
Cos(60) =
/2 = 1/2
Cos(45) =
/2 =
/2
Cos(30) =
/2 =
/2
Cos(0) =
/2 = 1
Subtract the y then add the 4 to the other side so y=0