Answer:
The probability is 0.683
Step-by-step explanation:
To calculate this, we shall be needing to calculate the z-scores of both temperatures
mathematically;
z-score = (x-mean)/SD
From the question mean = 78 and SD = 5
For 73
z-score = (73-78)/5 = -5/5 = -1
For 83
z-score = (83-78)/5 = 5/5 = 1
So the probability we want to calculate is within the following range of z-scores;
P(-1 <z <1 )
Mathematically, this is same as ;
P(z<1) - P(z<-1)
Using the normal distribution table;
P(-1<z<1) = 0.68269 which is approximately 0.683
Answer:
<1 = 33 degrees
<2 = 33 degrees
<3 = 114 degrees
Step-by-step explanation:
<1 and <2 = x
<3 = 3x+15
<1 + <2 + <3 = 180 degree
x + x + 3x + 15 = 180
5x = 180 - 15
x = 165/5
x = 33
<3 = 3(33)+15
= 114 degrees
Answer:
B
Step-by-step explanation:
We cannot assume independence for the employees sampled from location A.