Answer:
mean = 70000
SD = 15239
X= 95000
Z = (X-mean)/ SD
= (95000-70000)/15239
= 1.64
Now from Z-Table
% of employees = 100(1-.9495) = 5.02%
Answer:
The magnitude of the electric force between these two objects
will be: 181.274 N.
i.e. F
N
Step-by-step explanation:
As
Two object accumulated a charge of 4.5 μC and another a charge of 2.8 μC.
so
q₁ = 4.5 μC = 4.5 × 10⁻⁶ C
q₂ = 2.8 μC = 2.8 × 10⁻⁶ C
separated distance = d = 2.5 cm
Calculating the magnitude of the force between two charged objects using the formula:


∵ 
∵ 


∵ 
∵ 

F
N
Therefore, the magnitude of the electric force between these two objects will be: 181.274 N.
i.e. F
N
First write the equation
3/n = 5
Multiply both sides by n
3/n * n = 5 * n
Simplify
3 = 5 * n
Divide both sides by 5
3/5 = 5 * n/5
Simplify
3/5 = n
Divide
0.6 = n
So 3/0.6 = 5