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crimeas [40]
3 years ago
10

The Measure Of (Arc)XY is 94*. What is the measure of XYZ, The Tangent-chord Angle?

Mathematics
2 answers:
Delicious77 [7]3 years ago
6 0

Answer:

Option A. 47°

Step-by-step explanation:

Since m(Arc)XY = 94°

Therefore angle at the center = 94°

Now in triangle formed at the center  

∠XOY = 94°

Now ∠OXY+∠XYO = 180 - ∠YOX = 180 - 94 = 86

and we know ∠OXY = ∠XYO

therefore ∠XYO = 86/2 = 43°

Now ∠XYO + ∠XYZ = 90°

∠XYZ = 90 - ∠XYO = 90 - 43 = 47°

Option A 47° is the answer.

Musya8 [376]3 years ago
3 0
Hello,

The tangent-chord angle is the half of the center angle
==>94°/2=47°
Answer A
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Answer:

$325.00

Step-by-step explanation:

250*2=500+150=650/2=325

5 0
4 years ago
Need some help with these problems please.
goldenfox [79]

Answer:

See below.

Step-by-step explanation:

a.  

Divide the leading terms:

6x^4 / 2x^2 = 3x^2

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as x ---> +/- infinity r(x) ----> + infinity. (answer).

b.

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= 200.

So r(x) as a horizontal asymptote at y ( r(x)) = 200.  (answer).

3 0
3 years ago
A basketball has a circumference of 31.4 using 3.14 as an approximation for pie what is the basketball's volume to the nearest c
Andre45 [30]
C=2pir
V=(4/3)pir^3
solve for V

C=31.4
31.4=2pir
divide by 2
15.7=pir
divide both sides by pi or 3.14
5=r

V=(4/3)pir^3
V=(4/3)pi5^3
V=(4/3)pi125
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4 0
4 years ago
A physical therapist wants to determine the difference in the proportion of men and women who participate in regular sustained p
Studentka2010 [4]

Using the z-distribution, it is found that the needed sample sizes are:

a) 242

b) 1842

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which z is the z-score that has a p-value of \frac{1+\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99% confidence level, hence\alpha = 0.99, z is the value of Z that has a p-value of \frac{1+0.99}{2} = 0.995, so z = 2.575.

Item a:

The estimate is:

\pi = 0.223 - 0.189 = 0.034

The sample size is <u>n for which M = 0.03</u>, then:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 2.575\sqrt{\frac{0.034(0.966)}{n}}

0.03\sqrt{n} = 2.575\sqrt{0.034(0.966)}

\sqrt{n} = \frac{2.575\sqrt{0.034(0.966)}}{0.03}

(\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.034(0.966)}}{0.03}\right)^2

n = 241.97

Rounding up, a sample of 242 is needed.

Item b:

No prior estimates, hence \pi = 0.5 is used.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 2.575\sqrt{\frac{0.5(0.5)}{n}}

0.03\sqrt{n} = 2.575\sqrt{0.5(0.5)}

\sqrt{n} = \frac{2.575\sqrt{0.5(0.5)}}{0.03}

(\sqrt{n})^2 = \left(\frac{2.575\sqrt{0.5(0.5)}}{0.03}\right)^2

n = 1841.8

Rounding up, a sample of 1842 is needed.

For more on the z-distribution, you can check brainly.com/question/25404151

5 0
3 years ago
I need help now please ​
enyata [817]

Answer:

the 3rd one

Step-by-step explanation:

5 0
3 years ago
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