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Maru [420]
3 years ago
11

At an amusement park john wants to ride a rollercoaster that costs 19 tickets, a bumper car that costs 3 tickets, and a merry-go

-round that costs 33 tickets. John had 31 tickets but lost 10 of them on a ride. How many more tickets does he need?
Mathematics
1 answer:
N76 [4]3 years ago
3 0

Answer:

John will need 34 more tickets to be able to go on all the rides he wants

Step-by-step explanation:

To solve this, we need to first of all know the total cost in terms of tickets of all the rides that john wants to have.

This will be

cost of roller coaster ride = 19 tickets

cost of bumper car ride = 3 tickets

cost of merry-go-round ride = 33 tickets

Total cost of rides = 19 + 3 + 33 =55 tickets

Next, we will need to find the number of tickets that John has left after losing 10 of them.

This will be 31 - 10 = 21 tickets left

To find the number of more tickets that John needs , we will subtract the number of tickets he has left from total ride ticket cost.

This will be 55-21 = 34 tickets.

Hence, John will need 34 more tickets to be able to go on all the rides he wants

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Answer:

44.87°

Step-by-step explanation:

5 0
2 years ago
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A clinical trial tests a method designed to increase the probability of conceiving a girl. In the study 335335 babies were​ born
strojnjashka [21]

Answer:

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

Step-by-step explanation:

Confidence Interval for the proportion:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 335, \pi = \frac{268}{335} = 0.8

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 - 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.7437

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.8 + 2.575\sqrt{\frac{0.8*0.2}{335}} = 0.8563

For the percentage:

Multiplying the proportions by 100.

The 99​% confidence interval estimate of the percentage of girls born is (74.37%, 85.63%).

Usually, 50% of the babies are girls. This confidence interval gives values considerably higher than that, so the method to increase the probability of conceiving a girl appears to be very effective.

7 0
3 years ago
If f(x) = 5x, what is f–1(x)?
Verdich [7]
We are given f(x) = 5x
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Step 1:
Replace f(x) by y.
So,

y = 5x

Step 2:
Isolate x
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x = y/5

Step 3:
Replace x by f'(y)
So,

f'(y) = y/5

Step 4:
Replace all occurrences of y by x.
So,

f'(x) = x/5

Therefore, the inverse of f(x) = 5x is f'(x) = x/5
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Simplified form of 4(20 12) divided (4-3)
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What is the Slope of this equation?<br><br> y=-6/5x-5
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Answer:

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Step-by-step explanation:

Step 1:

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Step 2:

m = Slope

Step 3:

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Answer:

Slope = - 6/5

Hope This Helps :)

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