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Gekata [30.6K]
3 years ago
7

In which direction do hurricanes in the southern hemisphere rotate?

Physics
1 answer:
charle [14.2K]3 years ago
5 0
They should rotate clockwise
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Find the speed required to throw a ball straight up and it return 6 seconds later. Neglect air resistance
Nadya [2.5K]

Answer:

the ball will go up 3s and down 3s

v=gt

where t=3s and g=9.8m/s^2

distance=v0(t)+(1/2)gt^2

where initial velocity (v0)=0

Explanation:

8 0
3 years ago
Why the efficiency of carnot engine is not 100%
SVEN [57.7K]

Well, actually a heat engine using the Carnot cycle whose cold reservoir is maintained at 0 K could in principle be 100% efficient, even if the hot reservoir was merely at the ambient temperature. Since it costs no energy at all to maintain a heat reservoir at the ambient temperature as long as you have a perfect thermal connection to a large thermal capacitor like your swimming pool or a nearby aquifer you’d have built a perpetual motion machine.

3 0
3 years ago
If the light rays in the incident ray originate at 20º from the surface...
Ainat [17]

Given :

The light rays in the incident ray originate at 20º from the surface.

To Find :

The angle for the incident ray.

Solution :

We know angle of incidence is measured from perpendicular to the surface .

So,

\theta_i = 90^o - 20^o\\\\\theta_i = 70^o

Now, we know by law of reflection :

Angle of reflection = Angle of incident

\theta_r = 70^o

Therefore, the angle of incident and reflection is 70° each.

5 0
3 years ago
Why do you think that the speeds of comets increase as they near the sun
Lina20 [59]
Because the force of gravity attracts the comets towards the sun
6 0
4 years ago
Projectile A is launched horizontally at a speed of 20 meters per second from the top of a cliff and strikes a level surface bel
pogonyaev

Answer: 3 seconds

Explanation:

Initial velocity(u) of projectile A in vertical direction = 0m/s

acceleration due to gravity a=g=9.81m/s^2

Time taken(t) of projectile A = 3s

Initial velocity of projectile B = 0m/s(vertical direction)

We can get height of cliff using parameters of projectile A since it's the same location.

Height(S) = u×t + 0.5×a×t^2

u =0

S= 0.5×9.81×3^2 = 44.145m

Time taken for projectile B to reach the ground:

S = u×t + 0.5×a×t^2

u =0, S=44.145m, a=9.81m/s^2

44.145 = 0.5×9.81×t^2

44.145 = 4.905×t^2

44.145 ÷ 4.905 = t^2

9 = t^2

t = sqrt(9)

t = 3seconds

5 0
4 years ago
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