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FrozenT [24]
3 years ago
5

MAFS.5.NF.2.5a

Mathematics
1 answer:
Mademuasel [1]3 years ago
5 0

C would be the answer

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3. if kx² + 2x + k = -kx have equal roots, find the values of k.<br>​
crimeas [40]

Answer:

k = - \frac{2}{3} , k = 2

Step-by-step explanation:

Using the discriminant Δ = b² - 4ac

The condition for equal roots is b² - 4ac = 0

Given

kx² + 2x + k = - kx ( add kx to both sides )

kx² + 2x + kx + k = 0 , that is

kx² + (2 + k)x + k = 0 ← in standard form

with a = k, b = 2 + k and c = k , thus

(2 + k)² - 4k² = 0 ← expand and simplify left side

4 + 4k + k² - 4k² = 0

- 3k² + 4k + 4 = 0 ( multiply through by - 1 )

3k² - 4k - 4 = 0 ← in standard form

(3k + 2)(k - 2) = 0 ← in factored form

Equate each factor to zero and solve for k

3k + 2 = 0 ⇒ 3k = - 2 ⇒ k = - \frac{2}{3}

k - 2 = 0 ⇒ k = 2

5 0
3 years ago
Find the Arithmetic mean<br> between 6 and 12​
mafiozo [28]

Step-by-step explanation:

Arithmetic mean

A.M. =  \frac{6 + 12}{2}  =  \frac{18}{2}  = 9 \\

6 0
3 years ago
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Step-by-step explanation:

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(-INFINITY , -2) (3 , INFINITY)

Function is positive when above the x axis

Function is below the x axis between -2 and 3

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2 years ago
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