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svet-max [94.6K]
3 years ago
5

Will the difference between 44,041 and 43,876 be greater or less than, 1,000 explain

Mathematics
1 answer:
ololo11 [35]3 years ago
4 0

Answer:

Less

Step-by-step explanation:

44,041 - 43,876 is 165 and that is less than 1,000.

You might be interested in
Differentiate the following Functions<br> 5x^2-2xy + 4y^3= 5
Step2247 [10]

Answer:

\displaystyle y' = \frac{y - 5x}{x + 6y^2}

General Formulas and Concepts:

<u>Algebra I</u>

  • Terms/Coefficients
  • Factoring

<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation
  • Implicit Differentiation

Derivative Property [Multiplied Constant]:                                                           \displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)

Derivative Property [Addition/Subtraction]:                                                         \displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)]

Basic Power Rule:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Derivative Rule [Product Rule]:                                                                             \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Derivative Rule [Chain Rule]:                                                                                 \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle 5x^2 - 2xy + 4y^3 = 5

<u>Step 2: Differentiate</u>

  1. Implicit Differentiation:                                                                                 \displaystyle \frac{dy}{dx}[5x^2 - 2xy + 4y^3] = \frac{dy}{dx}[5]
  2. Rewrite [Derivative Property - Addition/Subtraction]:                                 \displaystyle \frac{dy}{dx}[5x^2] - \frac{dy}{dx}[2xy] + \frac{dy}{dx}[4y^3] = \frac{dy}{dx}[5]
  3. Rewrite [Derivative Property - Multiplied Constant]:                                   \displaystyle 5\frac{dy}{dx}[x^2] - 2\frac{dy}{dx}[xy] + 4\frac{dy}{dx}[y^3] = \frac{dy}{dx}[5]
  4. Basic Power Rule [Chain Rule]:                                                                     \displaystyle 10x - 2\frac{dy}{dx}[xy] + 12y^2y' = 0
  5. Product Rule:                                                                                                 \displaystyle 10x - 2\bigg[ \frac{dy}{dx}[x]y + x\frac{dy}{dx}[y] \bigg] + 12y^2y' = 0
  6. Basic Power Rule [Chain Rule]:                                                                     \displaystyle 10x - 2\bigg[ y + xy' \bigg] + 12y^2y' = 0
  7. Simplify:                                                                                                         \displaystyle 10x - 2y + 2xy' + 12y^2y' = 0
  8. Isolate <em>y'</em> terms:                                                                                             \displaystyle 2xy' + 12y^2y' = 2y - 10x
  9. Factor:                                                                                                           \displaystyle y'(2x + 12y^2) = 2y - 10x
  10. Isolate <em>y'</em>:                                                                                                       \displaystyle y' = \frac{2y - 10x}{2x + 12y^2}
  11. Factor:                                                                                                           \displaystyle y' = \frac{2(y - 5x)}{2(x + 6y^2)}
  12. Simplify:                                                                                                         \displaystyle y' = \frac{y - 5x}{x + 6y^2}

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

6 0
3 years ago
Please help the question is in the picture
Sedaia [141]

Answer:

-5√3 - 5√7/4

Step-by-step explanation:

Please mark me as brainliest

5 0
3 years ago
PLEASE HELP I NEED THIS 100 PLEASE GIVE ME THE CORRECT ANSWER YOU WILL GET THE BRAINLIEST PLEASE HELP
Aleksandr [31]
X= 135° y= 65° z= 70°
6 0
3 years ago
Find the length of BC​
Likurg_2 [28]

Answer:

BC = 88.88

Step-by-step explanation:

Comment.

This looks like an example of the cos law.

Givens

AB = 100 m

<A = 60 degrees

AC = 70 m

Cos(60) = 1/2

BC = ?

Formula

BC^2  = AB^2 + AC^2 - 2*AB*AC * Cos(60)

Solution

BC^2 = 100^2 + 70^2 - 2*100*70 * 1/2     1/2 and 2 cancel out

BC^2 = 10000 + 4900 - 7000      

BC^2 = 7900                                             Take the sqr root of both sides

√BC^2 = √7900

BC = 88.88

8 0
2 years ago
Original price: $32 ;Markup: 12.5% ;what is Retail Price
Trava [24]
12.5% = .125
32 x .125 = 4
32 + 4 = $36
6 0
3 years ago
Read 2 more answers
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