First, think of your places. You have the ones places, tens places, hundreds places, and so on.
The first number starting from the right is the ones, and as you keep going left, the value of each given digit becomes higher.
Since 5 is in the ones place, its value would be just 5. If it were in the tens place, it would be 50. If it were in the hundreds place, it would be 500, and so on.
Think of it this way;
Ones is just one. If a number is in the 'ones' place, its value would be a single digit. If it were in the tens place, its value would be two digits.
That's how it would be for each place going left.
Every number you move to the left, its value gains a one.
So here's an example:
5555
The value of 5 in the ones place "5555" is simply 5.
In the tens place, you end up adding one zero, so the value of the second five to the left would be, "50"
So with that said, the value of the digit 5 in the number 75 is <em>5.
</em>Haha, hope this cleared up any confusion, and have a <em>wonderful </em>day! :)<em>
</em>
Here, you have to foil the equation.
Distribute 4x to all sides, then distribute the -3 to all sides. Next, combine like terms. If you do this, your answer will be
Answer:
- The scientist can use these two measurements to calculate the distance between the Earth and the Sun by applying one of the trigonometric functions: Cosine of an angle.
- The scientist can substitute these measurements into
and solve for the distance between the Earth and the Sun.
Step-by-step explanation:
Let's assume that the right triangle formed is like the one shown in the figure attached, where "d" represents the distance between the Earth and the Sun.
Then:
The scientist can use only these two measurements to calculate the distance between the Earth and the Sun by applying one of the trigonometric functions: Cosine of an angle.
The scientist can substitute these measurements into
, and solve for the distance "d".
Knowing that:
![\alpha=x\°\\adjacent=d\\hypotenuse=y](https://tex.z-dn.net/?f=%5Calpha%3Dx%5C%C2%B0%5C%5Cadjacent%3Dd%5C%5Chypotenuse%3Dy)
Then:
![cos(x\°)=\frac{d}{y}](https://tex.z-dn.net/?f=cos%28x%5C%C2%B0%29%3D%5Cfrac%7Bd%7D%7By%7D)
And solving for "d":
![ycos(x\°)=d](https://tex.z-dn.net/?f=ycos%28x%5C%C2%B0%29%3Dd)
−<span>2.8
</span>Okay so "0.9x-1.3=-3.1" x=-2
<span><span><span>0.9x</span>−1.3</span>=<span>−3.1
</span></span>add 1.3 to both sides
<span><span><span><span>0.9x</span>−1.3</span>+1.3</span>=<span><span>−3.1</span>+1.3
</span></span><span><span>0.9x</span>=<span>−1.8
</span></span>divide both sides by 0.9
<span><span><span>0.9x/</span>0.9</span>=<span><span>−1.8/</span><span>0.9
</span></span></span>x=<span>−2</span>
So if you plug in -2 into "x-0.8" you get −2.8
<span>=<span><span>−2</span>−0.8
</span></span><span>=<span><span>−2-</span><span>0.8
</span></span></span><span>=<span>−2.8
</span></span>Hope this helps.