Distributive property 12kn+8k

Mathematics

1 answer:

soldier1979 [14.2K]3 years ago

7 0

4k(3n+2) this is basically just factoring out a common multiple which in this case is a k and a 4

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The weekly ad for a local grocery store advertises a 5 pound bag of organic apples for $13.95. Round each rate to the nearest hu

stich3 [128]

Answer:

Step-by-step explanation:

Given that in the weekly ad 5 pound bag of organic apples will cost 13.95 dollars

To find unit rate

Unit rate can be found in two ways either cost of 1 apple or no of apples for 1 dollars

I part:

5 apples = 13.95 dollars

1 apple = 13.95/5 (since direct variation)

Unit rate for one apple= 2.79 dollars

Part II:

13.95 dollars = 1 apple

1 dollar = 1/13.95 = 0.071

=0.07

But normally since apples are countable as 1,2 ... we use the first type of rate only unit rate per apple

6 0

3 years ago

find the average rate of change from t=2 to t=5 for the velocity function v(t)=t^2-t+10. WILL GIVE THE BRAINLIEST ANSWER--EXPLAI

Elina [12.6K]

Answer: The average rate of change is 6.
First, plug in each value of <em>t</em> into the function, v(t) to find there coordinate pairs.

v(2) = (2)^2 - (2) + 10
v(2) = 4 + 8
v(2) = 12

v(5) = (5)^2 - (5) + 10
v(5) = 25 + 5
v(5) = 30

You can write these values as coordinate pairs, like so: (2, 12) and (5, 30).
The formula for the average rate of change is $A(x) = \frac{f(x)-(f(a)}{x-a}$ . When you plug in the values from this particular case, the average rate of change formula becomes $A(t) = \frac{30-12}{5-2}$ , or $A(t)= \frac{18}{3}$ .

Looking at the equation, you can solve for the average rate of change between t = 2 and t = 5, which equals 6.

8 0

3 years ago

What is the product in simplest form x^2+9x+18/x+2 times x^2-3x-10/x^2+2x-24

german

$\dfrac{x^2+9x+18}{x+2}\cdot\dfrac{x^2-3x-10}{x^2+2x-24}=\dfrac{x^2+6x+3x+18}{x+2}\cdot\dfrac{x^2-5x+2x-10}{x^2+6x-4x-24}\\\\=\dfrac{x(x+6)+3(x+6)}{x+2}\cdot\dfrac{x(x-5)+2(x-5)}{x(x+6)-4(x+6)}$

$=\dfrac{(x+6)(x+3)}{x+2}\cdot\dfrac{(x-5)(x+2)}{(x+6)(x-4)}=\dfrac{(x+3)(x-5)}{x-4}\\\\=\dfrac{x^2-5x+3x-15}{x-4}=\dfrac{x^2-2x-15}{x-4}$