Answer:
TP: 13
Step-by-step explanation:
A=((b1+b2)/2)*h
100=((8+32)/2)*h
100=(40/2)*h
100=20h
h=5
A=8*5+((32-8)/2)*0.5*5*2
100=40+(24/2)*5
60=12*5
thus, point E is is 12 away from T
Triangle TPE:
the catets are TE:12 and PE:5
Lets use the Pythagorean theorem:
a^2+b^2=c^2
12^2+5^2=c^2
144+25=c^2
169=c^2
c=(+/-)13
since distance can only be positive, the answer is:
segment TP has the length of 13 units
Percentages? Are you sure that’s not a mistake
Answer: subtract 12-4
Step-by-step explanation:
For the range you subtract the smallest number from the biggest number so 12-4.
56.52 ÷ pi(3.14) = 18
18 ÷ 2 =9
A = pi(3.14)r^2
A = 3.14 × 9^2
A = 3.14 × 81
A = 254.34in^2
Draw number line from -5 to 10. .number that line.
Then show a point in 9 and -4
I hope that's what you mean from question
