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olga2289 [7]
3 years ago
13

HELP ASAP Solve: 7a + 10 = 2a​

Mathematics
2 answers:
Sveta_85 [38]3 years ago
8 0

Answer:

x=5

Step-by-step explanation:

sjjdbdjfjrndkodd

Nadya [2.5K]3 years ago
7 0

Answer:

a = -2

Step-by-step explanation:

7a + 10 = 2a​

subtract 2a from both sides

5a + 10 = 0

subtract 10 from both sides

5a = -10

divide both sides by 5

a = -2

hope this helps

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a merchant buys a telivision for $125 and sells it for the reatail price of $200. what is the markup.
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Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

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Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

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