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adell [148]
3 years ago
11

Is { (4,5) , (8,9) , (5,6) , (2,3) } a function? and why or why not?

Mathematics
1 answer:
Misha Larkins [42]3 years ago
4 0

Answer:

it is a function because the x's do not repeat

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If x2 – 49 = (x+a) (x – a), what is the value of a?
Ivenika [448]

<em>Answer:</em>

a = 7 & a = −7

<em>Explanation:</em>

Rewrite the equation as

(x+a)(x−a)=x^2−49

Simplify (x+a)(x−a)

x^2−a^2=x^2−49

Move all terms not containing a to the right side of the equation.

−a^2=−49

Multiply each term in −a^2=−49 by −1

a^2=49

Take the square root of both sides of the equation to eliminate the exponent on the left side.

a=±√49

The complete solution is the result of both the positive and negative portions of the solution.

a=7,−7

7 0
4 years ago
Read 2 more answers
147 centigrams is equivalent to how many grams
Vladimir79 [104]
147 is equivalent to 1.47 grams
8 0
3 years ago
What is the perimeter of square EFGH, shown?<br><br> A. 14.1<br> B. 28.3<br> C. 34.6<br> D. 17.3
kap26 [50]

Answer:

The perimeter of square EFGH is 28.28 units

Step-by-step explanation:

Given in the figure as :

EFGH is a square with points E,F,G,H

∵  The measure of each points from center o is same

I.e OE = OF = OG = OH = 5 units

Now, From any of two length from center o , we can measure the length of each side .

So, (OG)² + (OF)² = (GF)²

Or, (5)² + (5)² = (GF)²

Or,   25 + 25  = (GF)²

Or,     (GF)²  = 50

∴       GF =  5 \sqrt{2}  unit

Similarly each side EF, GH , EH have same length

Now, As The perimeter of square = 4 × side

So,          The perimeter of square = 4 × ( 5 \sqrt{2} )

Or,          The perimeter of square = 20 × ( \sqrt{2} ) = 28.28 unit

Hence The perimeter of square EFGH is 28.28 units   Answer

6 0
3 years ago
Please help the ( ) means to multiply please help for 15 points
KonstantinChe [14]

Answer:

outside the quotents means to multiply yes but inside means you do that problem first as in the order of PEMDAS Parentheses exponents multiply divide add subtract

Step-by-step explanation:

3 0
3 years ago
Please helpppppp!!!!!
azamat
Let they meet after second car travels for x hours'
let v be the speed  of second car and V be speed of first car.
Then time taken by first car=x+2
V(x+2)=vx (distance covered is same.)
\frac{v}{V} = \frac{x+2}{x} &#10;subtract 1 from both sides&#10; \frac{v-V}{V} = \frac{2}{x} &#10;v-V= \frac{2V}{x}


4 0
4 years ago
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