[5(14-2)^2]/2=
(5•12^2)/2=
5•144/2=
5•72=
720/2= 360
Box and whiskers plots use five number summaries. The first number is:
1:Minimum
2.Quartile 1
3.Mean
4.Quartile 2
5.maximum
Quartile are simple to get.
If your set of numbers is:
2,3,3,6,8,8,11
Then find the mean
2 3 3 |6| 8 8 11
Find the mean of the left side of of mean.
2 |3| 3 3 =Quartile 1
Then the right side
8 |8| 11 8 =Quartile 2
-----------------------------------------------
Your 5 number summary is 2,3,6,8,11
Plot them on the number line, but put a line above where the dot would go. take the 3 middle lines and connect to make a box. The lines on the outside of the box are the whiskers, AKA distributed data.
Answer:
12 cm²
Step-by-step explanation:
Length of rectangle = 5.6 cm
Width of rectangle = 2.1 cm
Area of rectangle = Length of rectangle×Width of rectangle
⇒Area of rectangle = 5.6×2.1
⇒Area of rectangle = 11.76 cm²
11.76 has 4 significant figures in order to write this term in 2 significant terms we round of the term
The last digit in the decimal place is 6. Now, 6≥5 so we round the next digit to 8 we get
11.8
Now the last digit in the decimal place is 8. Now, 8≥5 so we round the next digit to 2 we get
12
∴ Hence the area of the rectangle when rounded to 2 significant figures is 12 cm²
Answer:
The dimensions of the herb garden in the scale drawing are 2.4 in. by 6 in
Step-by-step explanation:
we know that
The dimensions of the garden in the actual are 10 ft by 5 ft
The dimensions of the garden on the scale drawing are 12 in. by 6 in
step 1
Find the scale factor
To find the scale factor divide the corresponding side on the scale drawing by the corresponding side in the actual
so
simplify
That means
1.2 inches in the drawing represent 1 foot in the actual
step 2
Find out the dimensions of the herb garden on the scale drawing
we know that
The dimensions of the herb garden in the actual are 2 ft by 5 ft
Multiply by the scale factor
so
therefore
The dimensions of the herb garden in the scale drawing are 2.4 in. by 6 in
<span>Length = l</span>
<span>
Width = w</span>
<span>
Perimeter = p = 100
</span>
<span>Perimeter of rectangle = 2(l+w)</span>
<span>
100 = 2 (4w + w)</span>
<span>
100 = 2(5w)</span>
<span>
100 = 10w</span>
<span>
100/10 = w</span>
<span>
10 = w</span>
<span>
w = 10
Area of rectangle = length * width</span>
<span>
a = l*w</span>
<span>
a = 4w*w</span>
<span>
a = 4w^2............(1)</span>
<span>
Put the value of w in (1)</span>
<span>
a = 4(10)^2</span>
<span>
a= 4(100)</span>
<span>
a = 400 yd^2</span>
