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il63 [147K]
3 years ago
15

What is the probability that a red 10 is drawn in a regular deck of cards?

Mathematics
2 answers:
kvv77 [185]3 years ago
8 0
5.2 because the standard size deck of cards is 52 and you have to divide that by the possible outcome
Advocard [28]3 years ago
6 0

Answer:

1/26 or 1 out of 26

Step-by-step explanation:

only 2 red tens

52 cards in a deck

2/52=1/26

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Please help ASAP Plzzzz
damaskus [11]

Answer:

10,10

Step-by-step explanation:

you got this

6 0
2 years ago
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How do I solve #7? do i add all the angles together like a normal triangle and make it equal to 180?
kobusy [5.1K]

Answer:

126 degrees

Step-by-step explanation:

Triangle: y = 180 - (5x + 4x)

Straight angle: y = 180 - (4x + 30)

180 - (5x + 4x) = 180 - (4x + 30)

5x + 4x = 4x + 30

5x = 30

x = 6

Angle:

y = 180 - (5x + 4x)

y = 180 - 9x

y = 180 - 9(6)

y =  126

7 0
2 years ago
Suppose that each child born is equally likely to be a boy or a girl. Consider a family with exactly three children. Let BBG ind
Gemiola [76]

Answer:

(a)

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

(b)

i.

1\ girl = \{GBB, BBG, BGB\}

P(1\ girl) = 0.375

ii.

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

P(Atleast\ 2 \ girls) = 0.5

iii.

No\ girl = \{BBB\}

P(No\ girl) = 0.125

Step-by-step explanation:

Given

Children = 3

B = Boys

G = Girls

Solving (a): List all possible elements using set-roster notation.

The possible elements are:

S = \{GGG, GGB, GBG, GBB, BBG, BGB, BGG, BBB\}

And the number of elements are:

n(S) = 8

Solving (bi) Exactly 1 girl

From the list of possible elements, we have:

1\ girl = \{GBB, BBG, BGB\}

And the number of the list is;

n(1\ girl) = 3

The probability is calculated as;

P(1\ girl) = \frac{n(1\ girl)}{n(S)}

P(1\ girl) = \frac{3}{8}

P(1\ girl) = 0.375

Solving (bi) At least 2 are girls

From the list of possible elements, we have:

Atleast\ 2 \ girls = \{GGG, GGB, GBG, BGG\}

And the number of the list is;

n(Atleast\ 2 \ girls) = 4

The probability is calculated as;

P(Atleast\ 2 \ girls) = \frac{n(Atleast\ 2 \ girls)}{n(S)}

P(Atleast\ 2 \ girls) = \frac{4}{8}

P(Atleast\ 2 \ girls) = 0.5

Solving (biii) No girl

From the list of possible elements, we have:

No\ girl = \{BBB\}

And the number of the list is;

n(No\ girl) = 1

The probability is calculated as;

P(No\ girl) = \frac{n(No\ girl)}{n(S)}

P(No\ girl) = \frac{1}{8}

P(No\ girl) = 0.125

7 0
3 years ago
Anyone ...Pls solve
expeople1 [14]
Given:
- Bought n items of product A at 1/5 rs each
- bought n items of product B at 1/4 rs each
He mixed the two items and sold each at 2/9 rs each.
He lost 3 rs in the above batch of articles.

Solution:
revenue = 2n* (2/9) rs = 4n/9 rs
cost = n/5+n/4 rs = n(1/5+1/4)
Profit = revenue-cost = 4n/9-n(1/5+1/4) = -3 rs

Solve for n
4n/9-n(1/5+1/4) = -3 
factor out n
n(4/9-1/5-1/4)=-3
n(80-36-45)/180=-3
-n/180=-3
n=3*180=540

Total number of products bought
= n+n = 540+540 = 1080
6 0
3 years ago
Uncle drew scored 28 points in 5 5/6 minutes during a game of basketball.
Lina20 [59]

The answer is \frac{24}{5} = 4\frac{4}{5} points per minute

8 0
3 years ago
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