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BartSMP [9]
4 years ago
11

Two joggers run 8 miles north and then 5 miles west what they is the shortest distance to the nearest tenths of a mile they must

travel to return to their starting point
Mathematics
1 answer:
balandron [24]4 years ago
8 0

Answer:

Step-by-step explanation:

Use pythagoras: a^2+b^2=c^2

so rearrange to b^2=a^2-c^2

so 8^2-5^2

64-25=39

Square root

square root of 39 is 6.2 miles is the answer

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For binomials of the form (x - y) ^ n explain how to determine the sign of a term without writing out the entire expansion
Mnenie [13.5K]

Answer:

When raising an expression of that format to any power, after grouping like terms, you'll always find that the odd numbered terms are positive, and the even numbered terms are negative.

For example:

(x - y)² = x² − 2xy + y²

(x - y)³ = x³ − 3x²y + 3xy² − y³

(x - y)⁴ =x⁴ − 4x³y + 6x²y² − 4xy³ + y⁴

etc.

3 0
3 years ago
8qt equals gallon and qt​
joja [24]

Answer:

2 Gallons

Step-by-step explanation:

1 Gallon = 4 quarts

There are 8 quarts, and 8 divided by 4 is 2.

2 Gallons.

5 0
4 years ago
If a right triangle, the acute angles measure x+15 and 2x degrees. What is the measure of the smallest angle of the triangle?
saveliy_v [14]

Answer:

The measure of the smallest angle of the triangle is  40.

Step-by-step explanation:

A right triangle adds up to 180

x+15+2x+90=180

Combine like terms

3x+105=180

Subtract both sides by 105

3x+105=180

   -105=-105

___________

3x=75 Divide by 3

x=25

Plug in 25 for x for equation expression

90=90

25+15=40

2(25)=50

Therefore for the smallest angle is 40

Hope this helps

6 0
3 years ago
Algebra need help ASAP !!!
kirza4 [7]
The top one on the left is equivalent to the second one down on the right; the second one down on the left is equivalent to the bottom one on the right; the third one down on the left is equivalent to the second one down on the right, and the last one on the left is the only one remaining on the right.
7 0
3 years ago
use the quadratic formula to find the zeros of the function round to the tense of necessary y= 17x^2-21
Kitty [74]
y=17x^2-21\\\\\text{The zeros of the function:}\ y=0\iff17x^2-21=0\ \ \ |+21\\\\17x^2=21\ \ \ |:17\\\\x^2=\dfrac{21}{17}\to x=\pm\sqrt{\dfrax{21}{17}}\\\\x\approx-1.1\ \vee\ x\approx1.1

\text{Use the quadratic formula:}\\\\y=17x^2-21\\\\a=17;\ b=0;\ c=-21\\\\b^2-4ac=0^2-4\cdot17\cdot(-21)=1428\\\\x_1=\dfrac{-b-\sqrt{b^2-4ac}}{2a};\ x_2=\dfrac{-b+\sqrt{b^2-4ac}}{2a}\\\\x_1=\dfrac{-0-\sqrt{1428}}{2\cdot17}=-\dfrac{\sqrt{1428}}{34}\approx-1.1\\\\x_2=\dfrac{-0+\sqrt{1428}}{2\cdot17}=\dfrac{\sqrt{1428}}{34}\approx1.1
6 0
3 years ago
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