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BartSMP [9]
4 years ago
11

Two joggers run 8 miles north and then 5 miles west what they is the shortest distance to the nearest tenths of a mile they must

travel to return to their starting point
Mathematics
1 answer:
balandron [24]4 years ago
8 0

Answer:

Step-by-step explanation:

Use pythagoras: a^2+b^2=c^2

so rearrange to b^2=a^2-c^2

so 8^2-5^2

64-25=39

Square root

square root of 39 is 6.2 miles is the answer

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Answer:

1/2

Step-by-step explanation:

The interior of the square is the region D = { (x,y) : 0 ≤ x,y ≤1 }. We call L(x,y) = 7y²x, M(x,y) = 8x²y. Since C is positively oriented, Green Theorem states that

\int\limits_C {L(x,y)} \, dx + {M(x,y)} \, dy = \int\limits^1_0\int\limits^1_0 {(Mx - Ly)} \, dxdy

Lets calculate the partial derivates of M and L, Mx and Ly. They can be computed by taking the derivate of the respective value, treating the other variable as a constant.

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Thus, Mx(x,y) - Ly(x,y) = 2xy, and therefore, the line ntegral is equal to the double integral

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\int\limits^1_0\int\limits^1_0 {2xy} \, dxdy = \int\limits^1_0 {x^2y} |^1_0 \,dy = \int\limits^1_0 {y} \, dy = \frac{y^2}{2} \, |^1_0 = 1/2

We conclude that the line integral is 1/2

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