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Anvisha [2.4K]
3 years ago
11

QUSTUN 5

Mathematics
2 answers:
MaRussiya [10]3 years ago
8 0

Answer:

It removes the repeating part of the decimal from the equation.

kotykmax [81]3 years ago
5 0

Answer:

It removes the repeating part of the decimal from the equation.

Step-by-step explanation:

Described here is the process of converting the repeating decimal fraction into fraction in the form of p/q

1) --------------

  • x = 0.555555

2) --------------

  • 10x = 5.555555

3) --------------

  • 10 x - x = 5.555555 - 0.555555
  • 9x = 5
  • x = 5/9

So the purpose of step 3 here is to remove the repeating part of the decimal from the equation

Correct option is the first one.

You might be interested in
Given h(x) = –2 – 3, find h(-6).
igomit [66]

Answer

3

Step-by-step explanation:

h(-6)=-(-6)-3

h(-6)=6-3

h(-6)=3

4 0
3 years ago
the ratio of girls to boys in the sixth grade is 5:3. If there are 400 sixth graders, how many boys are there?
PilotLPTM [1.2K]

Answer:

boys = 250

girls = 150

Step-by-step explanation:

5g = 3b       eq. 1

g + b = 400       eq. 2

g = girls

b = boys

From the eq. 2

g = 400 - b

Replacing this last eq. on eq. 1:

5(400-b) = 3b

5*400 + 5*-b = 3b

2000 - 5b = 3b

2000 = 3b + 5b

2000 = 8b

2000/8 = b

250 = b

From eq. 2

g + 250 = 400

g = 400 - 250

g = 150

Check:

from eq. 1

5*150 = 3*250  = 750

3 0
2 years ago
The graph of a sinusoidal function has a minimum point at (0,3)(0,3) and then intersects its midline at (5π,5)
bekas [8.4K]

Answer: F(x) = 2*sin(x/10  +(3/2)*pi) + 5

Step-by-step explanation:

The information that we have is that:

We have a minimum at (0, 3)

the midline is at (5*pi, 5)

This is a sinusoidal function, so we can write one generic one as:

F(x) = A*sin(c*x + p) + B.

where A and B are constants, c is the frequency and p is a phase

First, the minimum of the sine function is when sin(x) = -1, and this happens at (3/2)*pi

We know that this minimum is at x = 0.

sin(c*0 + p) = -1

Then p = 3/2*pi.

So our function is:

F(x) = A*sin(c*x  +(3/2)*pi) + B.

Now, we know that F(0) = 3, so:

3 = A*sin(c*0 +(3/2)*pi) + B = -A + B.

now we can use the other hint, the midpoint of the sine function is when sin(x) = 0, and this happens at x = 0 and x = pi, particularlly as we here have a phase of 3/2*pi, we should find x = 2*pi.

then:

c*5*pi + (3/2)*pi = 2*pi

c*5 + 3/2 = 2

c*5 = 2 - 3/2 = 1/2

C = 1/2*5 = 1/10

So our function is

F(x) = A*sin(x/10  +(3/2)*pi) + B

and we know that when x = 5*pi, F(5*pi) = 5, so:

5 = F(x) = A*sin(5*pi/10  +(3/2)*pi) + B

5 = B

and we aready knew that:

- A + B = 3

-A + 5 = 3

A = 5 - 3 = 2

So our equation is:

F(x) = 2*sin(x/10  +(3/2)*pi) + 5

8 0
3 years ago
Please help please and thank you
Katyanochek1 [597]

Step-by-step explanation:

\text{We know:}\\\\\sin(-\alpha)=-\sin\alpha\\\\\sin(\alpha\pm k\cdot360^o)=\sin\alpha\\\\===============================\\\\\sin(360^o-\theta)=\sin\bigg(-(\theta-360^o)\bigg)=-\sin(\theta-360^o)=-\sin\theta

3 0
3 years ago
horace is running a race. he begins to wonder how fast he is running. which unit rates would be reasonable for horace to use to
tresset_1 [31]
<span>Horace is running a race. he begins to wonder how fast he is running.
</span>km/h will best describe how fast he is running.

8 0
3 years ago
Read 2 more answers
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