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3 years ago

QUSTUN 5

Mathematics

2 answers:

MaRussiya [10]3 years ago

8 0

Answer:

It removes the repeating part of the decimal from the equation.

kotykmax [81]3 years ago

5 0

Answer:

It removes the repeating part of the decimal from the equation.

Step-by-step explanation:

Described here is the process of converting the repeating decimal fraction into fraction in the form of p/q

1) --------------

x = 0.555555

2) --------------

10x = 5.555555

3) --------------

10 x - x = 5.555555 - 0.555555
9x = 5
x = 5/9

So the purpose of step 3 here is to remove the repeating part of the decimal from the equation

Correct option is the first one.

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brilliants [131]

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4 years ago

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A farm stand sells apples pies and jars of applesauce. The table shows the number of apples needed to

Galina-37 [17]

Answer:

Step-by-step explanation:

3 0

3 years ago

Find all real zeros of t f(x)=x-14x² + 47x-18

BabaBlast [244]

Answer:

x=3/7 and x= 3

Step-by-step explanation:

First simplify:

-14 x^2 +48x -18

divide everything by -2

-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)

-2 (x^2 -24x +63)

-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21

-2 [(x-3/7)(x-21/7)]

-2 [(7x-3)(x-3)]

Hence, the zeroes are 3/7 and 3

Hope this helps!

If you think I helped, Please mark brainliest! Would really appreciate!

4 0

3 years ago

Please answer There is a bag filled with 3 blue and 5 red marbles. A marble is taken at random from the bag, the colour is noted

Misha Larkins [42]

Answer:

$\frac{15}{28}$ is the required probability.

Step-by-step explanation:

Total number of Marbles = Blue + Red $= 3 + 5 = 8$

Probability of getting blue $= \frac{3}{8}$

Probability of not getting a blue $=\frac{5}{8}$

To get exactly one blue in two draws, we either get a blue, not blue, or a not blue, blue.

First Draw Blue, Second Draw Not Blue:

1st Draw: $P(Blue) = \frac{3}{8}$

2nd Draw: $P(Not\:Blue)=\frac{5}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{3}{8}\cdot \frac{5}{7}=\frac{15}{56}$

First Draw Not Blue, Second Draw Not Blue:

1st Draw: $P(Not\:Blue)=\frac{5}{8}$

2nd Draw: $P(Not\:Blue)=\frac{3}{7}$ (since we did not replace the first marble)

To get the probability of the event, since each draw is independent, we multiply both probabilities.

$P(Event)=\frac{5}{8}\cdot \frac{3}{7}=\frac{15}{56}$

To get the probability of exactly one blue, we add both of the events:

$\frac{15}{56}+\frac{15}{56}=\frac{15}{28}$

4 0

3 years ago

Define a substitution method to solve the followingsysten of equation of y=2x-3, x+y=1

Ivan

I will solve you system by substitution

y = 2x - 3 ; x + y = 1

→Step 1: Solve y = 2x - 3 for y

→Step 2: Substitute 2x - 3 for y in x + y = 1:

x + y = 1

x + 2x- 3 = 1

3x - 3 = 1 (Simplify both sides of the equation)

3x - 3 + 3 = 1 + 3 (Add 3 both sides)

3x = 4

3x ÷ 3 = 4 ÷ 3 (Divide each side by 3)

x = 4/3

→Step 3: Substitute 4/3 for x in y = 2x - 3:

y = 2x - 3

y = 2 (4/3) -3

y = -1/3 (Simplify both sides of the equation)

Answer:

x = 4/3 and y = -1/3

∫Hope that helps∫

7 0

3 years ago