Answer:
The answer is "Option A".
Explanation:
The interactive background advertisements, that use advanced internet navigation technology from Google to dynamically resolve specific information demands based on the quality of a network page are also referred to as interactive search ads. This ads are good for tactics, and certain options were incorrect, that can be defined as follows:
- In option B, It allows you easily access all other URLs of creative online ads.
- In option C, It helps regulate operation in a machine.
- In option D, It grows the internet traffic.
Answer:
"cost, schedule, technical, and organizational feasibility schedule" is the correct option.
Explanation:
A technical feasibility is the study of the concerned about the specifying software and tools which satisfy the users' need. It is also the process of thinking for which business technologies are important to bring labours, transportation, and materials.
An organizational feasibility is the study of the information of the professional background and about the skills which are necessary for the contribution in the business.
Answer / Explanation:
195.200.0.0/16
Note: Class C address can not be assigned a subnet mask of /16 because class c address has 24 bits assigned for network part.
2ⁿ = number of subnets
where n is additional bits borrowed from the host portion.
2ˣ - 2 = number of hosts
where x represent bits for the host portion.
Assuming we have 195.200.0.0/25
In the last octet, we have one bit for the network
number of subnets = 2¹ =2 network addresses
number of host = 2⁷ - 2= 126 network addresses per subnets
Answer:
sectors
Explanation:
hard disk contain tracks which are further divided into sectors, for storage purposes.
Answer:
// This program is written in C++
// Comments are used for explanatory purpose
// Program starts here
#include<iostream.h>
#include<stdlib.h>
int main()
{
// Declare variables
int num, selectno;
string status;
randomize();
//Generate random number;
num=rand()%10000;
// Prompt to guess a number
cout<<"You have only 10 tries\nTake a guess: ";
int tries = 0;
while (tries != 10)
{
cin>>selectno;
if(selectno == num){
cout<<"You passed at the "<<count+1<<" attempt";
tries = 10;
}
else
{
cout<<"You failed. Take another guess\n You have "<<10 - count + 1 <<" attempts";
}
tries++;
if(tries >= 10)
{
break;
}
}
return 0;
}
